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3 years ago

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What is the description for magnetic field lines?

1 answer:

valentina_108 [34]3 years ago

6 0

A pictorial representation of magnetic field lines is very useful in visualizing the strength and direction of the magnetic field . The direction of magnetic field lines is defined to be the direction in which the north end of a compass needle points.

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An emf of 22.0 mV is induced in a 519-turn coil when the current is changing at the rate of 10.0 A/s. What is the magnetic flux

zhenek [66]

Answer:

$\phi=1.56\times 10^{-5}\ Wb$

Explanation:

Given that,

Emf, V = 22 mV

Number of turns in the coil us 519

Rate of change of current is 10 A/s.

We need to find the magnetic flux through each turn of the coil at an instant when the current is 3.70 A.

Let's find the inductance first. So,

$L=\dfrac{\epsilon}{(dI/dt)}\\\\L=\dfrac{0.022}{10}\\\\L=0.0022\ H$

We have,

$L=\dfrac{N\phi}{I}$ , $\phi$ is magnetic flux

$\phi=\dfrac{LI}{N}\\\\\phi=\dfrac{0.0022\times3.7}{519}\\\\\phi=1.56\times 10^{-5}\ Wb$

So, the magnetic flux is $1.56\times 10^{-5}\ Wb$ .

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3 years ago

The unusually bright centers found in some galaxies are called ______.

Nimfa-mama [501]

<span>Active Galactic Nuclei.</span>

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3 years ago

A bowling ball has a mass of 7.2 kg and a weight of 70.6 N. It moves down the bowling alley at 1 m/s and strikes a pin with a fo

Inga [223]

The answer is 15.0N its explained in newtons third law hope this helps:)

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3 years ago

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Which type of galaxy often contains the largest relative amount of gas and dust?

Vikki [24]

the answer is spiral galaxies

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3 years ago

The Atwood machine consists of two masses hanging from the ends of a rope that passes over a pulley. Assume that the rope and pu

Kisachek [45]

Answer:

$a=2.36\ m/s^2$

T=157.06 N

Explanation:

Given that

Mass of first block = 21.1 kg

Mass of second block = 12.9 kg

First mass is heavier than first that is why mass second first will go downward and mass second will go upward.

Given that pulley and string is mass less that is why both mass will have same acceleration.So lets take their acceleration is 'a'.

So now from force equation

$m_1g-m_2g=(m_1+m_2)a$

21.1 x 9.81 - 12.9 x 9.81 =(21.1+12.9) a

$a=2.36\ m/s^2$

Lets tension in string is T

$m_1g-T=m_1a$

$T=m_1(g-a)$

T=21.1(9.81-2.36) N

T=157.06 N

6 0

3 years ago