All categories

3 years ago

Why is there such a large jump and ionization energy between the second and third ionization energy‘s for magnesium?

1 answer:

5 0

The second ionization energy of Mg is larger than the first because it always takes more energy to remove an electron from a positively charged ion than from a neutral atom. The third ionization energy of magnesium is enormous, however, because the Mg2+ ion has a filled-shell electron configuration.

You might be interested in

g In the elimination reaction of t-butanol and t-butyl bromide. A. They have a common intermediate and require a strong base B.

11111nata11111 [884]

Answer:

Both reactions share a common intermediate and differ only in the leaving group

Explanation:

The elimination reaction of tertiary alkyl halides usually occur by E1 mechanism. In E1 mechanism, the substrate undergoes ionization leading to the loss of a leaving group and formation of a carbocation.

Loss of a proton from the carbocation completes the reaction mechanism yielding the desired alkene.

In the cases of t-butanol and t-butyl bromide, the mechanism is the same. The both reactions proceed by E1 mechanism. The leaving groups in each case are water and chloride ion respectively.

6 0

3 years ago

Britney added 0.05 moles of copper(II) nitrate solution to 0.1 moles of sodium hydroxide solution and

Rama09 [41]

The percent yield of copper hydroxide is 84%

<h3>Stoichiometry</h3>

From the question, we are to determine the percent yield of copper hydroxide

First, we will determine the theoretical mass

From the given balanced chemical equation, we have

Cu(NO₃)₂ + 2NaOH -- Cu(OH)₂ + 2NaNO₃

This means,

1 mole of copper(II) nitrate reacts with 2 moles of sodium hydroxide to produce 1 mole of copper hydroxide

Therefore,
0.05 mole of copper(II) nitrate reacts with 0.1 mole of sodium hydroxide to produce 0.05 mole of copper hydroxide

The theoretical number of moles of copper hydroxide that is produced is 0.05 mole

Now, for the theoretical mass

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of copper hydroxide = 97.56 g/mol

Then,

Theoretical mass = 0.05 × 97.56

Theoretical mass of copper of hydroxide produced is = 4.878 g

Now, for the percent yield of copper hydroxide

Percent yield is given by the formula,

$Percent\ yield = \frac{Actual\ yield}{Theoretical\ yield} \times 100\%$

Then,

$Percent\ yield\ of\ copper\ hydroxide= \frac{4.1}{4.878}\times 100\%$

$Percent\ yield\ of\ copper\ hydroxide= 84\%$

Hence, the percent yield of copper hydroxide is 84%.

Learn more on Stoichiometry here: brainly.com/question/9372758

7 0

3 years ago

what is the molarity of a solution that contains 30.0 g kcl in enough water to make 100 ml of a solution

shusha [124]

Answer:

397043

Explanation:

4 0

3 years ago

Which of the following cannot be separated by physical means?

Elina [12.6K]

The correct answer is D Elements

8 0

3 years ago

216 grams of carbon 36 grams of hydrogen and 288 grams of oxygen whats the empirical formula

schepotkina [342]

Divide each wight by the relative atomic mass

C = 216 / 12 = 18
H = 36 / 1 = 36
O = 288/16 = 18

Ratio of C:h:O = 1:2:1

Empirical formula is CH2O Could be formaldehyde HCHO.

4 0

3 years ago

Why is there such a large jump and ionization energy between the second and third ionization energy‘s for magnesium￼?

Why is there such a large jump and ionization energy between the second and third ionization energy‘s for magnesium?