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zubka84 [21]
3 years ago
8

Which of the following will be most soluble in octane?

Chemistry
1 answer:
natima [27]3 years ago
7 0

Answer:

CH3CH3CH2CH3

Explanation:

Octane is a non-polar compound. It is a hydrocarbon with 8-carbon length along its chain.

It belongs to a special group of hydrocarbons called alkanes.

What makes a substance soluble in another?

   It is a common phrase that  "like dissolves like". This is applicable to solubility of substances in another.

  • A polar solvent will freely and easily dissolve a polar solute. For example, water and salt.
  • A non-polar solvent will also dissolve a non-polar solute. This case, hydrocarbons will dissolve themselves.
  • The first option is a butane, a 4-carbon length hydrocarbon which will be dissolved in octane.
  • Both compounds are non-polar.
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Pls help me with this
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Answer:

[I_2]=[Br]=0.31M

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to set up the following chemical equation at equilibrium:

I_2+Br_2\rightleftharpoons 2IBr

Now, we can set up the equilibrium expression in terms of x (reaction extent) whereas the initial concentration of both iodine and bromine is 0.5mol/0.250L=2.0M:

K=\frac{[IBr]^2}{[I_2][Br_2]} \\\\1.2x10^2=\frac{(2x)^2}{(2.0-x)^2}

Thus, we solve for x as show below:

\sqrt{1.2x10^2} =\sqrt{\frac{(2x)^2}{(2.0-x)^2}} \\\\10.95=\frac{2x}{2.0-x}\\\\21.91-10.95x=2x\\\\21.91=12.95x\\\\x=\frac{21.91}{12.95} \\\\x=1.69M

Therefore, the concentrations of both bromine and iodine are:

[I_2]=[Br]=2.0M-1.69M=0.31M

Regards!

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