Given data:
Diameter of the gold wire (d) = 0.175 cm
Length of the gold wire (l) = 1.00 *
cm
Volume of the given gold wire = volume occupied by a cylindrical object\
= π *
*l
here r = radius of the cross section
where : r = d/2
Hence the volume V = π *
*l
= 
Density of gold = 19.3 g/cm3
Weight of the gold wire = Density * volume
=
*
= 
Answer:
<h2>1.505 × 10²⁴ particles</h2>
Explanation:
The number of particles in iron (II) chloride can be found by using the formula
<h3>N = n × L</h3>
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 2.5 × 6.02 × 10²³
We have the final answer as
<h3>1.505 × 10²⁴ particles</h3>
Hope this helps you
Answer:
Reagent A = 
Reagent B= 
Intermediate C= δ-Valerolactone
Explanation:
In the reaction from the alkene to the alcohol, we can use the <u>alkene hydration</u> in which the hydronium ion is added to the double bond followed by the attack of water to produce the <u>alcohol</u>.
Then in the conversion from alcohol to ketone can be produced if an <u>oxidant reactive</u><u> </u>is used. In this case the <u>Jones reagent </u>(
).
The intermediate is a structure produced by a <u>peroxyacid</u>. This reaction would introduce an <u>ester group </u>in the cycle generating the δ-Valerolactone (Figure 1).