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Ierofanga [76]
3 years ago
11

When you see or visit grasslands, what do you know about the climate? (Select all that apply.)

Chemistry
2 answers:
denis23 [38]3 years ago
5 0

Answer:

They have little precipitation.

They have cold winters.

They have mild to hot summers.

Nana76 [90]3 years ago
4 0

When you see  or visit grasslands you know that :

  • They have mild to hot summers ( B )
  • They have a lot of precipitation  ( A )

<h3><u>Grassland vegetation</u> </h3>

Grasslands are a type of vegetation found mostly in areas with favourable weather conditions such as mild summers and right amount of precipitation which provides the grasslands with enough water for proper growth.

Other types of vegetation include :

  • Forest vegetation
  • Tundra  and
  • Desert vegetation

Desert vegetation expreciences very hot summers and little precipitation which leads to the scarcity of green vegetation, while forest vegetation expreciences a very high level of precipitation.

Hence we can conclude that When you see  or visit grasslands you know that :They have mild to hot summers ,They have a lot of precipitation  

Learn more about grasslands : brainly.com/question/994161

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Please help me for question 1 and 2
likoan [24]

Answer:-

1) 6 mol

2) Mo

Explanation: -

Mass of Ozone = 48 g

Chemical formula of ozone = O3

Molar mass of Ozone O 3 = 16 x 3 = 48 g mol-1

Number of moles of ozone = Mass / molar mass

= 48 g / 48 g mol-1

= 1 mol

According to Avogadro’s law, 1 mole of a substance has 6.02 x 10^ 22 molecules.

So 1 mol of O3 has 6.02 x 10^ 22 molecules of ozone.

Now each Ozone molecule has 3 atoms of oxygen.

So, 1 mol of ozone has 3 x 6.02 x 10^22 atoms of oxygen.

Sodium must have 2 x 3 x 6.02 x 10^22 atoms as per the question.

According to Avogadro’s law, 6.02 x 10^ 22 atoms are in 1 mol of sodium

So, for 2 x 3 x 6.02 x 10^22 atoms, there should be (1/ 6.02 x 10^ 22) x 2 x 3 x 6.02 x 10^22

= 6 mol of sodium.

b)

Let the mass of M be m g

Formula of hexafluoride = MF6.

Mass of the hexafluoride = g + 6 x 19

= m + 114

Mass of M=0.250g

Moles of M = 0.250/m

Mass of MF6= 0.547g

Moles of MF6 = 0.547/ (m + 114)

We know 1 mole of M gives 1 mole of MF6.

0.250/m moles of M gives 0.250/m moles of MF6.

But number of moles of MF6 = 0.547/ (m + 114)

Thus

0.250/m = (0.547)/ (m +114))

0.250m + 0.250 x 114 = 0.547m

m = 0.250 x 114 / (0.547 -0.250)

= 96

We see from the given data that Mo is 96.

So M is Mo.

4 0
3 years ago
How many moles are in 234.4 grams of oxygen
uysha [10]

Answer:

7.325 mol.

Explanation:

use the formula n=m/mr

so that makes:

234.4/16*2

which is 7.325 mol.

4 0
3 years ago
A scientist plants two rows of corn for experimentation. She puts fertilizer on row 1 but does not put fertilizer on row 2. Both
IrinaVladis [17]

Answer:

Q9. The independent variable in this experiment is the fertilizer. It is independent because she manipulating the variable to compare the growth.

Q10. The dependent variable in this experiment is the amount of growth of the corn. It is this because the growth depends on what the scientist did on the corn.

Q11. The variable controlled in this experiment is the amount of sun and water. These two variables never change so this is why it is the control.

Explanation:

5 0
3 years ago
Read 2 more answers
How many moles are present in
olasank [31]

Answer: (a) There are 0.428 moles present in 12 g of N_{2} molecule.

(b) There are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

Explanation:

(a). The mass of nitrogen molecule is given as 12 g.

As the molar mass of N_{2} is 28 g/mol so its number of moles are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{12 g}{28 g/mol}\\= 0.428 mol

So, there are 0.428 moles present in 12 g of N_{2} molecule.

(b). According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

Therefore, moles present in 12.044 \times 10^{23} particles are calculated as follows.

Moles = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}}\\= 2 mol

So, there are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

4 0
3 years ago
How many grams of methane gas occupy a volume of 11.2 liters at stp
Anni [7]

Answer:

see the pic for the answer

4 0
3 years ago
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