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3 years ago

How much heat is required to increase the temperature of 20 grams of water by 26 degrees celsius?

Chemistry

1 answer:

mrs_skeptik [129]3 years ago

4 0

Answer: 2175.68 J heat is required to increase the temperature of 20 grams of water by 26 degrees celsius.

Explanation:

Given: Mass = 20 g

Change in temperature = $26^{o}C$

The standard value of specific heat of water is $4.184 J/ g^{o}C$

Formula used to calculate the heat energy is as follows.

$q = m \times C \times \Delta T$

where,

q = heat energy

m = mass of substance

C = specific heat of substance

$\Delta T$ = change in temperature

Substitute the values into above formula as follows.

$q = m \times C \times \Delta T\\= 20 g \times 4.184 J/g ^{o}C \times 26^{o}C\\= 2175.68 J$

Thus, we can conclude that 2175.68 J heat is required to increase the temperature of 20 grams of water by 26 degrees celsius.

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