<span>3. The attempt at a solution So basically what I did was divided into components. x: (3)(2000) = (3000)*v_x y: (v_vw)*(10000) = (3000)*v_y v_x, v_y is the velocity (after collision) in the x and y direction, respectively, of both cars stuck together (since it is an inelastic collision). v_vw is the initial velocity of the Volkswagen. Now what I did was that the angle is 35 degrees north of east. So basically made a triangle and figured that tan(35) = (v_y)/(v_x). This means (v_x)*(tan35) = v_y. Then, I simplified the component equations to get: x: 2 = v_x y: v_vw = 3*v_y Then plugging in for v_y, I got: v_vw = 3(2)(tan35) = 4.2 m/s as the velocity of the volkswagen. However, the answer key says 8.6 m/s. Could someone please help me out? Thanks Phys.org - latest science and technology news stories on Phys.org • Game over? Computer beats human champ in ancient Chinese game • Simplifying solar cells with a new mix of materials • Imaged 'jets' reveal cerium's post-shock inner strength Oct 24, 2012 #2 ehild Homework Helper Gold Member What directions you call x and y?
Reference https://www.physicsforums.com/threads/2d-momentum-problem.646613/</span>
Answer:a) λ = 4.862 10⁻⁷ m, b) λ = 4.341 10⁻⁷ m
Explanation:
The spectrum of hydrogen can be described by the expression
in the case of the initial state n = 2 this series is the Balmer series
a) Find the wavelength for n = 4
let's calculate
= 1,097 10⁷ ()
\frac{1}{ \lambda} = 1.097 10⁷ 0.1875 = 0.2056 10⁷
λ = 4.862 10⁻⁷ m
b) n = 5
\frac{1}{ \lambda} = 1,097 10⁷ ()
\frac{1}{ \lambda} = 1.097 10⁷ 0.21 = 0.23037 10⁷
λ = 4.341 10⁻⁷ m
Answer:
Explanation:
Acceleration = a change in velocity / a change in time
Acceleration = ( final velocity - initial velocity) / a change in time
Acceleration = (6m/s - 35 m/s ) / 5 s
= (-29 m/s) /( 5 s)
= - 5.8 m/s^^2
Remember Significant Figures
- 6 m/s^2
P.S I have no idea why the answers say m/s because acceleration is m/s^2.
:)
Answer:
the cart's speed at point B is 15.72 ft/s
Explanation:
Given the data in the question;
The car travels from point A to C in 3.00 s, its average acceleration 
will be;
= [
- 
] / Δt
is 17.4 ft/s, is 13.2 ft/s and Δt is 3.00 s
so we substitute
= [17.4 - 13.2] / 3
= 4.2 / 3
= 1.4 ft/s²
so average acceleration of the cart between the points A and B is 1.4 ft/s²
The instantaneous value of the velocity of the cart at point B will be;
= Δv / Δt
now substitute [ - 
] for Δv and t' for Δt
= [ - ] / t'
= - ( t' )
so we substitute 17.4 ft/s for , 1.20 s for t' and = 1.4 ft/s²
= 17.4 - (1.4 × 1.20)
= 17.4 - 1.68
= 15.72 ft/s
Therefore, the cart's speed at point B is 15.72 ft/s
Rmax = 4Hmax, that happen if the elevation of a projectile is 45°
