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Fiesta28 [93]
3 years ago
7

I will mark you BRAINLIEST if you give correct step by step answer

Mathematics
1 answer:
vova2212 [387]3 years ago
8 0

(i)

f(x) = x^2\\\\\frac{f(x +h) - f(x)}{h} = \frac{(x + h)^2 - x^2}{h} = \frac{x^2 + 2xh + h^2 - x^2}{h} = \frac{2xh + h^2}{h} = \frac{h(2x + h)}{h} = 2x + h

(ii)

f(x) = 3x + 5\\\\\frac{f(x + h) - f(x)}{h} = \frac{3(x + h) + 5 - (3x + 5)}{h} = \frac{3(x + h) + 5 - 3x - 5}{h} = \frac{3x + 3h + 5 - 3x - 5}{h} = \frac{3h}{h} = 3

(iii)

f(x) = x^2 + 3x + 6\\\\\frac{f(x + h) - f(x)}{h} = \frac{(x + h)^2 + 3(x +h) + 6 - (x^2 + 3x + 6)}{h} = \frac{x^2 + 2xh + h^2 + 3x + 3h + 6 - x^2 - 3x - 6}{h} = \frac{2xh + h^2 + 3h}{h} = \frac{h(3x + h + 3)}{h} = 2x +h + 3

(iv)

f(x) = x^3 + 1\\\\\frac{f(x + h) - f(x)}{h} = \frac{(x + h)^3 + 1 - (x^3 + 1)}{h} = \frac{(x + h)^3 + 1 - x^3 - 1}{h} = \frac{x^3 + 3x^2h + 3xh^2 + h^3 + 1 - x^3 - 1}{h} = \frac{3x^2h + 3xh^2 + h^3}{h} = \frac{h(3x^2 + 3xh + h^2)}{h} = 3x^2 + 3xh + h^2

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  5. Division
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Step-by-step explanation:

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y = 3

y = -3x + 6

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute in <em>y</em>:                                                                                                 3 = -3x + 6
  2. [Subtraction Property of Equality] Subtract 6 on both sides:                      -3 = -3x
  3. [Division Property of Equality] Divide -3 on both sides:                                1 = x
  4. Rewrite/Rearrange:                                                                                        x = 1

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                                                                               y = -3(1) + 6
  2. Multiply:                                                                                                           y = -3 + 6
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