9514 1404 393
Answer:
A, C, B
Step-by-step explanation:
It is helpful to remember the trig identities ...
sin = 1/csc
cos = 1/sec
tan = 1/cot
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1. sin(θ)cos(θ)sec(θ)csc(θ) = (sin(θ)csc(θ))(cos(θ)sec(θ)) = (1)(1) = 1 . . . matches A
2. 1/cot²(θ)·sec(θ)cos(θ) = 1/(1/tan²(θ))·(1) = tan²(θ) . . . matches C
3. tan(θ)/cot(θ) = tan(θ)/(1/tan(θ)) = tan²(θ) . . . matches B
1.sin Θ cos Θ sec Θ csc Θ
sinocoso×1/coso ×1/sino=1
1. is the required answer
2.1/(cot^2Θ) * sec Θ cos Θ
=sin²o/cos²o×1/coso×coso
=sin²o/cos²o
tan²o is answer
3.tan Θ/ cot Θ
sino/coso/(coso/sino)
sin²o/cos²o
tan²ois answer here o = theta
hey, hope this helps/ is right :))
Less than: 1/4, 1/8, 1/16,...
Greater than: 5/8, 3/4, 1,...
Hope this helps :)
Answer
b
Answer: y=-1/6x+2
Step-by-step explanation: The point goes through (0,2), aka, the b point in y=mx+b (The slope intercept form). Then because it’s proceeding downwards, we know that the slope is negative. So down one, over 6. This make its -1/6.
