Question

1. Which of the following is equivalent?

Answer 1

9514 1404 393

Answer:

  A, C, B

Step-by-step explanation:

It is helpful to remember the trig identities ...

  sin = 1/csc

  cos = 1/sec

  tan = 1/cot

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1. sin(θ)cos(θ)sec(θ)csc(θ) = (sin(θ)csc(θ))(cos(θ)sec(θ)) = (1)(1) = 1 . . . matches A

2. 1/cot²(θ)·sec(θ)cos(θ) = 1/(1/tan²(θ))·(1) = tan²(θ) . . . matches C

3. tan(θ)/cot(θ) = tan(θ)/(1/tan(θ)) = tan²(θ) . . . matches B

Answer 2

Answer:

1.sin Θ cos Θ sec Θ csc Θ

sinocoso×1/coso ×1/sino=1

1. is the required answer

2.1/(cot^2Θ) * sec Θ cos Θ

=sin²o/cos²o×1/coso×coso

=sin²o/cos²o

tan²o is answer

3.tan Θ/ cot Θ

sino/coso/(coso/sino)

sin²o/cos²o

tan²ois answer here o = theta