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Elza [17]
3 years ago
11

How many moles would you need to have 7.85 x 10^22 molecules of ammonia (NH3).

Chemistry
1 answer:
RSB [31]3 years ago
3 0
<h3>Answer:</h3>

0.130 moles NH₃

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 7.85 × 10²² molecules NH₃

[Solve] moles NH₃

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 7.85 \cdot 10^{22} \ molecules \ NH_3(\frac{1 \ mol \ NH_3}{6.022 \cdot 10^{23} \ molecules \ NH_3})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 0.130355 \ moles \ NH_3

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.130355 moles NH₃ ≈ 0.130 moles NH₃

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