Answer:
Step-by-step explanation:
We are given that a and b are rational numbers where 
and x is irrational number .
We have to prove a+bx is irrational number by contradiction.
Supposition:let a+bx is a rational number then it can be written in 
form
where 
where p and q are integers.
Proof:
After dividing p and q by common factor except 1 then we get
r and s are coprime therefore, there is no common factor of r and s except 1.
where r and s are integers.
When we subtract one rational from other rational number then we get again a rational number and we divide one rational by other rational number then we get quotient number which is also rational.
Therefore, the number on the right hand of equal to is rational number but x is a irrational number .A rational number is not equal to an irrational number .Therefore, it is contradict by taking a+bx is a rational number .Hence, a+bx is an irrational number.
Conclusion: a+bx is an irrational number.
36x just got done taking this
Answer:
− 3.5 ( x + y )
Hope this helps
Step-by-step explanation:
Answer:
g(x) = 
Step-by-step explanation:
This problem may seem tricky at first, but after you understand the basic concepts about vertical stretches and vertical shrinks, this problem will become much simpler. Additionally, if you use the online tool: DESMOS, you will be able visualize things better.
First, you may notice the graph is more narrow than the original "f(x)" graph. This means that the g(x) graph is a vertical shrink. A vertical shrink can be achieved by adding a whole-number as a coefficient to the "
" formula. Adding a coefficient of "5" would result in coordinates like (1,5), just like adding a coefficient of "2" for example would result in coordinates like (1,2).
Answer:
w + 10 = 40
Step-by-step explanation:
10 more than w is w + 10 is equal to 40 is =40
w + 10 = 40
Please mark as brainliest.
