M(P)=3.72 g
M(P)=31 g/mol
m(Cl)=21.28 g
M(Cl)=35.5 g/mol
n(P)=m(P)/M(P)
n(P)=3.72/31=0.12 mol
n(Cl)=m(Cl)/M(Cl)
n(Cl)=21.28/35.5=0.60 mol
P : Cl = 0.12 : 0.60 = 1 : 5
PCl₅ - is the empirical formula
The chemical contractor has to retrieve the chemical and a identification analysis would have to be conducted
Answer:
2.11 ×10²⁴ atoms
Explanation:
Given data:
Number of moles of NaCl = 3.5 mol
Number of atoms = ?
Solution:
It is known that 1 mole contain 6.022×10²³ atoms. The number 6.022×10²³ is called Avogadro number.
3.5 mol ×6.022×10²³ atoms / 1 mol
21.1 ×10²³ atoms
2.11 ×10²⁴ atoms
