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Vilka [71]
3 years ago
12

What is the flow rate of the air in the pipeline if the cross sectional area of a pneumatic pipeline is 0.01 m2 and the speed of

the air in the pipeline is 20 m/s?
Mathematics
1 answer:
e-lub [12.9K]3 years ago
7 0

Answer:

0.2 m³/s

Step-by-step explanation:

Applying,

Q = vA.............. Equation 1

Where Q = Flow rate of  air in the pipeline, v = flow velocity of the air in the pipeline, A = cross sectional area of the pneumatic pipeline.

From the question,

Given: v = 20 m/s, A = 0.01 m²

Substitute these values into equation 1

Q = 20(0.01)

Q = 0.2 m³/s

Hence the flow rate of air in the pipeline is  0.2 m³/s

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in a survey of a school 300 student favour to play volleyball 200 student favour to play cricket and 110 favour both find the nu
sweet [91]
If 110 students play both
The 300 that play volleyball includes them.
That’s mean that 190 (300-110) play only volleyball
Also (the same) 200 play cricket, so only cricket play 90 students (200-110)
Answer: either volleyball or cricket is
(300-110)+(200-110) = 190+ 90 = 280
Answer: 280
3 0
3 years ago
21 is 80% of what number
nikklg [1K]

<u>Answer:</u>

26.25

<u>Step-by-step explanation:</u>

21 is 80% of 26.25

Hopefully this helps :3 Sorry if wrong :( Plz mark brainiest if correct :D Your bootiful/handsome! Have a great day luv <3

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8 0
3 years ago
A school is tracking its freshmen attendance for the first marking period. Shown below is a table summarizing the findings for t
Talja [164]

Answer:

The median number of days absent is zero (0)

The mean number of days absent is 1.0 day

(b) The proportion of the population that has absenteeism greater than 4 days is 6.34 %

Step-by-step explanation:

total number of students, n = 284

The total number of students is even, the median number of days absent will in (n/2).

n/2 = 284/2 = 142

The cumulative frequency that falls in 148 students = 0 day

The median number of days absent is zero (0)

For mean:

Let the days absent = x  

let the number of students = f

mean (\bar x) =  \frac{\sum fx}{\sum f}\\\\\bar x =   \frac{(158\times 0)+ (64\times 1)+(18\times 2)+(22\times 3)+(4\times 4)+(5\times 7)+(6\times 8)+(9\times 2)+(13\times 1)}{284} \\\\\bar x = \frac{296}{284} \\\\\bar x = 1.0 \ day

(b) the number of students with absenteeism greater than 4 dyas;

= 7 + 8 + 2 + 1

= 18

The proportion of these students;

= \frac{18}{284} \\\\= 0.0634 \\\\= 6.34 \ \%

5 0
3 years ago
If I make a 40.2 on a test what fraction of the questions did I answer correctly
Kruka [31]

Answer:

You answered 201/500 of the questions correctly

Step-by-step explanation:

40.2/100=402/1000=201/500

6 0
4 years ago
Can someone please help me with this question?
scoray [572]
The answer is the first one
7 0
3 years ago
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