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2 years ago

Use complete sentences to differentiate between acids and bases on the basis of touch. Give an example of each type.

Chemistry

1 answer:

stellarik [79]2 years ago

6 0

<h2>Answer:</h2>

Acids are sour, gives burning sensation, generally sticky, reacts with metals to produce hydrogen gas.

example: Acetic acid

Bases are opposite as they are bitter, generally odorless (except ammonia), they are slippery;

example: sodium bicarbonate

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3 years ago

What is the new concentration of 25.0mL added to 125.0mL of 0.150M

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Answer:

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Explanation:

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3 years ago

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Answer: Farmers were paid to practice soil-conserving techniques like crop rotation and terracing

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3 years ago

Read 2 more answers

2. Matt went to his friend’s party. He ate a big meal and drank a keg of beer. He felt heartburn after the meal and took Tums to

evablogger [386]

Answer:

390.85mL

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 780 torr

Initial volume (V1) = 400mL

Initial temperature (T1) = 40°C = 40°C + 273 = 313K

Final temperature (T2) = 25°C = 25°C + 273 = 298K

Final pressure (P2) = 1 atm = 760torr

Final volume (V2) =?

Step 2:

Determination of the final volume i.e the volume of the gas outside Matt's body.

The volume of the gas outside Matt's body can be obtained by using the general gas equation as shown below:

P1V1/T1 = P2V2/T2

780 x 400/313 = 760 x V2 /298

Cross multiply to express in linear form

313 x 760 x V2 = 780 x 400 x 298

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V2 = (780 x 400 x 298) /(313 x 760)

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3 years ago

Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.

Jlenok [28]

<u>Answer:</u> The density of gold in $g/cm^3$ is $19.22g/cm^3$

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

$\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}$

We are given:

Density of gold = $1200lb/ft^3$

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1 lb = 453.6 g

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Converting given quantity into $g/cm^3$ , we get:

$\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3$

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3 years ago