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Verizon [17]
3 years ago
11

Given the balanced chemical equation for the decomposition for INO, and the rate of disappearance of INO, write the expressions

for the rates of appearance of I2 and NO.
2INO(g) → I2(g) + 2NO(g)

Reactant: Product(I2): Product(NO):

-∆[INO]/2∆t = ??/??
Chemistry
1 answer:
katovenus [111]3 years ago
8 0

Answer:

rate of disappearance of -0.5d[INO]/dt

rate of appearance of I2 = d[I2]/dt

rate of appearance of No = 0.5*d[NO]/dt

Explanation:

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Activation energy is: A. The maximum amount of energy reactants can hold. B. The energy needed to begin breaking the bonds of pr
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Activation energy is the energy needed to begin breaking the bonds of reactants and is denoted as option D.

<h3>What is a Reactant?</h3>

These are the substances which take part in a chemical reaction and result in the formation of the product.

The activation energy is required as it breaks the bonds of the reactant thereby resulting in the product being formed. This therefore makes it the most appropriate choice.

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2 years ago
20.0 g of bromic acid, HBrO3, is reacted with excess HBr.
Blababa [14]

After Rounding off The percentage yield is 64%

<h3>What is Percentage Yield ?</h3>

It is the ratio of actual yield to theoretical yield multiplied by 100% .

It is given in the question

20.0 g of bromic acid, HBrO3, is reacted with excess HBr.

The reaction is

HBrO₃ (aq) + 5 HBr (aq) → 3 H₂O (l) + 3 Br₂ (aq)

Actual yield = 47.3 grams

Molecular weight of Bromic Acid is 128.91 gram

Moles of Bromic Acid = 20/128.91 = 0.155 mole

Mole fraction ratio of Bromic Acid to Bromine is 1 :3

Therefore for 0.155 mole of Bromic Acid 3 * 0.155 = 0.465 mole of Bromine is produced.

1 mole of Bromine = 159.8 grams of Bromine

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Percentage Yield = (47.3/74.31)*100 = 63.65 %

After Rounding off The percentage yield is 64% .

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5 0
1 year ago
A student measures the mass of a 6.0 cm3 block of brown sugar to be 10.0 g. What is the density of the brown sugar?
Alex17521 [72]

Answer:

1.67g/cm3

Explanation:

The formula for density is d=\frac{m}{v} . The m variable stands for mass and the v variable stands for volume.

The mass of the brown sugar is 10.0g and the volume is 6.0cm3, so we can plug those values into the equation.

d=\frac{10g}{6cm^{3} }

d=1.67\frac{g}{cm^{3} }

Rounded to 3 significant figures, the density of the block of brown sugar is 1.67 g/cm3. If the mass is in grams and the volume is in cm3, the unit for the final answer is \frac{g}{cm^{3} } (grams per centimetres cubed).

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3 years ago
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An alloy is a mixture that has
defon

Answer:

an alloy is a mixture of elements that has metallic properties

Explanation:

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