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natima [27]
3 years ago
9

Classify the following as either an element, compound, homogeneous mixture or

Chemistry
1 answer:
Alecsey [184]3 years ago
6 0

Sodium chloride is the chemical name for salt and is composed of sodium and chlorine, so it is a compound.

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Mkey [24]
Answer:
D (hope I’m right, sorry if it’s not)
3 0
2 years ago
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Significant Figures For 7.06 × 10^5 ÷ 5.3 × 10^-2
Kay [80]

Answer:

\boxed{\text{two}}

Explanation:

In multiplication  and division problems, your answer can have no more significant figures than the number with the fewest significant figures.

\dfrac{7.06 \times 10^{5}}{5.3 \times 10^{-2}}= 1.332 075 472 \times 10^{7} (by my calculator)  

There are three significant figures in 7.06 and two in 2.3.

You must round to \boxed{\textbf{two}} significant figures and report the answer as 1.3 × 1.0⁷.

4 0
3 years ago
2AgNO3 + BaCl2 → 2AgCl + Ba(NO3)2
miv72 [106K]
<h3>Answer:</h3>

4 g AgCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN]   2AgNO₃ + BaCl₂ → 2AgCl + Ba(NO₃)₂

[Given]   5.0 g AgNO₃

<u>Step 2: Identify Conversions</u>

[Reaction - Stoich] 2AgNO₃ → 2AgCl

Molar Mass of Ag - 107.87 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

Molar Mass of AgCl - 107.87 + 35.45 = 143.32 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up:                              \displaystyle 5.0 \ g \ AgNO_3(\frac{1 \ mol \ AgNO_3}{169.88 \ g \ AgNO_3})(\frac{2 \ mol \ AgCl}{2 \ mol \ AgNO_3})(\frac{143.22 \ g \ AgCl}{1 \ mol \ AgCl})
  2. Multiply/Divide:                                                                                                  \displaystyle 4.21533 \ g \ AgCl

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

4.21533 g AgCl ≈ 4 g AgCl

3 0
3 years ago
When turgor pressure is high enough in a cell, the cell walls become _____
iren2701 [21]

Answer:

the answer is "Firm".

Explanation:

6 0
3 years ago
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PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
mezya [45]
Since Chlorine is in excess, this is a limiting reagent problem.
1) convert 11.50 g Na to g of NaCl using the balanced equation.
2) percent yield = (actual yield)/(potential yield).

.85= (actual yield)/(g from step 1)

Solve for actual yield
5 0
4 years ago
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