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vodomira [7]
3 years ago
9

Copy and balance these chemical equations "K​

Chemistry
1 answer:
alexdok [17]3 years ago
5 0

"K" is Potassium. If that is the answer you are needing.

You might be interested in
Calculate the molarity of a solution that contains 3.11 mol of NaNO3 dissolved in 2.50 L. Enter your answer in the provided box.
rusak2 [61]

Answer:

Molarity of a solution that contains 3.11 mol of NaNO3 is 1,24 M

Explanation:

We understand molarity as the number of moles of solute that are contained in 1 L of solution, then if in a solution of 2.50 L we have 3.11 moles, it remains to calculate how many moles do we have in 1 liter.

2,50 L .......... 3,11 moles

1 L .................. x

X = ( 1 L x 3,11 moles) / 2,50 L = 1,24

8 0
3 years ago
PLEASE HELP!!!!!!!!!
KonstantinChe [14]

Answer:

Option "C" is the correct answer to the following question.

Explanation:

Given:

Pressure in an automobile tire (P) = 1.88 atm

Temperature (K) = 25°C = 273 + 25 = 298 Kelvin

New temperature (K1) = 37°C = 273 + 37 = 310 Kelvin

Find:

New pressure in an automobile tire (P1) = ?

Computation:

\frac{P}{K}= \frac{P1}{K1} \\\\\frac{1.88}{298}= \frac{P1}{310}\\\\1.9557

New pressure in an automobile tire (P1) = 1.9557

New pressure in an automobile tire (P1) = 1.96 (Approx)

5 0
3 years ago
If 1.20 moles of copper react with mercuric nitrate how many moles of mercury form
Andrej [43]
Reaction of Copper with Mercuric Nitrate is as follow,

                       Cu  +  Hg(NO₃)₂    →    Cu(NO₃)₂  +  Hg

According to equation,

                            1 Mole of Cu reacts to form  =  1 Mole of Hg

So,

           1.20 Moles of Cu will react to produce  =  X Moles of Hg

Solving for X,

                                   X  =  (1.20 mol × 1 mol) ÷ 1 mol

                                   X  =  1.20 mol of Hg
Result:
          1.20 mole of Cu when reacted with mercuric nitrate produces 1.20 moles of Hg.
3 0
4 years ago
Can some one please help to understand this problem??<br><br><br>​
Rama09 [41]

Answer:

mercury, magnesium, water and gasoline.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

The liquid with higher density will sink in bottom while the liquid with lower density will float.

In given samples,

density of water = 1 g/mL

density of mercury = 13.6 g/mL

density of gasoline = 0.70 g/mL

density of magnesium = 1.7 g/mL

So on the basis of given density values mercury will sink in bottom then above it magnesium will present than water and above on these three gasoline will present.

6 0
3 years ago
A gas occupies 547 L at 331K. Find its volume at 376K. You must show all of your work to receive credit. Also, name the gas law
zysi [14]

621.4L

Explanation:

Given parameters:

Initial volume = 547L

Initial temperature = 331K

Final temperature = 376K

Unknown:

Final volume = ?

Solution:

The appropriate gas law to use is the Charles's law.

The Charles's law shows the relationship between the volume and temperature of a gas under constant pressure.

The law states that "The volume of a fixed of a gas varies directly as its absolute temperature if the pressure is constant".

Mathematically;

    \frac{V_{1} }{T_{1} }  = \frac{V_{2} }{T_{2} }

 V₁ is the initial volume

 T₁ is the initial temperature

 V₂ is the final volume

 T₂ is the final temperature

Since the unknown is the final volume, we make it the subject of the expression;

   V₂ = \frac{V_{1} }{T_{1} }  x T_{2}  = \frac{547}{331 }  x 376

 V₂ =  621.4L

learn more:

Boyle's law brainly.com/question/8928288

#learnwithBrainly

3 0
3 years ago
Read 2 more answers
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