Answer:
Molarity of a solution that contains 3.11 mol of NaNO3 is 1,24 M
Explanation:
We understand molarity as the number of moles of solute that are contained in 1 L of solution, then if in a solution of 2.50 L we have 3.11 moles, it remains to calculate how many moles do we have in 1 liter.
2,50 L .......... 3,11 moles
1 L .................. x
X = ( 1 L x 3,11 moles) / 2,50 L = 1,24
Answer:
Option "C" is the correct answer to the following question.
Explanation:
Given:
Pressure in an automobile tire (P) = 1.88 atm
Temperature (K) = 25°C = 273 + 25 = 298 Kelvin
New temperature (K1) = 37°C = 273 + 37 = 310 Kelvin
Find:
New pressure in an automobile tire (P1) = ?
Computation:

New pressure in an automobile tire (P1) = 1.9557
New pressure in an automobile tire (P1) = 1.96 (Approx)
Reaction of Copper with Mercuric Nitrate is as follow,
Cu + Hg(NO₃)₂ → Cu(NO₃)₂ + Hg
According to equation,
1 Mole of Cu reacts to form = 1 Mole of Hg
So,
1.20 Moles of Cu will react to produce = X Moles of Hg
Solving for X,
X = (1.20 mol × 1 mol) ÷ 1 mol
X = 1.20 mol of Hg
Result:
1.20 mole of Cu when reacted with mercuric nitrate produces 1.20 moles of Hg.
Answer:
mercury, magnesium, water and gasoline.
Explanation:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
The liquid with higher density will sink in bottom while the liquid with lower density will float.
In given samples,
density of water = 1 g/mL
density of mercury = 13.6 g/mL
density of gasoline = 0.70 g/mL
density of magnesium = 1.7 g/mL
So on the basis of given density values mercury will sink in bottom then above it magnesium will present than water and above on these three gasoline will present.
621.4L
Explanation:
Given parameters:
Initial volume = 547L
Initial temperature = 331K
Final temperature = 376K
Unknown:
Final volume = ?
Solution:
The appropriate gas law to use is the Charles's law.
The Charles's law shows the relationship between the volume and temperature of a gas under constant pressure.
The law states that "The volume of a fixed of a gas varies directly as its absolute temperature if the pressure is constant".
Mathematically;

V₁ is the initial volume
T₁ is the initial temperature
V₂ is the final volume
T₂ is the final temperature
Since the unknown is the final volume, we make it the subject of the expression;
V₂ = 
V₂ = 621.4L
learn more:
Boyle's law brainly.com/question/8928288
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