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ella [17]
3 years ago
12

The velocity (speed) of an object was determined to be 45 miles per

Chemistry
2 answers:
denis23 [38]3 years ago
7 0

Answer:

it is 72.9 km/h

Explanation:

just multiply 45 * 1.62 = ~72.9

Ahat [919]3 years ago
4 0

Answer: 72.58 km/hr

Explanation:

\frac{45 miles}{1 hour}×\frac{1 km}{0.62 miles} = 72.58 km/hr

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A solution is prepared by mixing 2.17 g of an unknown non-electrolyte with 225.0 g of chloroform. The freezing point of the resu
Deffense [45]

Answer:

The molar mass of the unknown non-electrolyte is 64.3 g/mol

Explanation:

Step 1: Data given

Mass of an unknown non-electrolyte = 2.17 grams

Mass of chloroform = 225.0 grams

The freezing point of the resulting solution is –64.2 °C

The freezing point of pure chloroform is – 63.5°C

kf = 4.68°C/m

Step 2: Calculate molality

ΔT = i*kf*m

⇒ ΔT = The freezing point depression = T (pure solvent) − T(solution) = -63.5°C + 64.2 °C = 0.7 °C

⇒i = the van't Hoff factor = non-electrolyte = 1

⇒ kf = the freezing point depression constant = 4.68 °C/m

⇒ m = molality = moles unknown non-electrolyte / mass chloroform

0.7 °C = 1 * 4.68 °C/m * m

m = 0.150 molal

Step 3: Calculate moles unknown non-electrolyte

molality = moles unknown non-electrolyte / mass chloroform

Moles unknown non-electrolyte = 0.150 molal * 0.225 kg

Moles unknown non-electrolyte = 0.03375 moles

Step 4: Calculate molecular mass unknown non-electrolyte

Molar mass = mass / moles

Molar mass = 2.17 grams / 0.03375 moles

Molar mass = 64.3 g/mol

The molar mass of the unknown non-electrolyte is 64.3 g/mol

6 0
3 years ago
Im doing a science project and need examples and non-examples of an Atom. some examples of an atom is neon, hydrogen, argon, etc
gogolik [260]

Answer:

Anything not on the periodic table is an element non example! ... So, for a substance to be an element, all of its atoms must have the same number of protons. Examples of elements include hydrogen, lithium, nickel, and radium.

Explanation:

6 0
3 years ago
What element makes protein different from carbohydrate and fat? select one:
Savatey [412]
D........... Nitrogen
8 0
3 years ago
3. Classify the following plants along with two main characteristics: al Cycus b) Bamboo c) Lemna d) Paddy a) Sugarcane f) Pinus
madreJ [45]

Answer:

A. cycas

1. it is thick and scaly

2. it grow relatively slowly and have a large, terminal rosette of leaves.

B. bamboo

1. it is very durable

2. it is both flexible and elastic

C. lemna

1. it grows as simple free-floating thalli on or just beneath the water surface

2. it are small, not exceeding 5 mm in length

D. paddy

1. it is variety purity

2. it degree of purity

E. sugarcane

1. it is bear long sword-shaped leaves

2. it's stalks are composed of many segments, and in each joint there is a bud

4 0
2 years ago
Is mud a heterogeneous or homogeneous mixture?
Lemur [1.5K]

Answer:

Heterogenous

Explanation:

Mud is a mixture of water and soil

8 0
3 years ago
Read 2 more answers
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