Ask question

Ask question

All categories

2 years ago

6

A 3.0-A current is maintained in a simple circuit that consists of a resistor between the terminals of an ideal battery. If the

battery supplies energy at a rate of 25 W, how large is the resistance

1 answer:

harina [27]2 years ago

7 0

Answer:

$R=2.78\ \Omega$

Explanation:

Given that,

The current flowing in the circuit, I = 3 A

The power of the battery, P = 25 W

We need to find the resistance of the battery. We know that the power of the battery is given by the formula as follows :

$P=I^2R$

Put all the values to find R.

$R=\dfrac{P}{I^2}\\\\R=\dfrac{25}{(3)^2}\\\\R=2.78\ \Omega$

So, the resistance is equal to $2.78\ \Omega$ .

You might be interested in

An object weigh 40N in air ,weigh 20N when submerged in water,and 30N when submerged in a liquid of unknown liquid density.what

muminat

Answer:

The density is $\rho_u =500 kg /m^3$

Explanation:

From the question we are told that

The weight in air is $W_a = 40 \ N$

The weight in water is $W_w = 20 \ N$

The weight in a unknown liquid is $W_u = 30 \ N$

Now according to Archimedes principle the weight of the object in water is mathematically represented as

$W_w = W_a -m _w g$

Where $m_w$ is he mass of the water displaced

substituting value

$m_w g = 40 -20$

$m_w g = 20 \ N --- (1)$

Now according to Archimedes principle the weight of the object in unknown is mathematically represented as

$W_u = W_a -m _u g$

Where $m_u$ is he mass of the unknown liquid displaced

substituting value

$m_u g = 40 -30$

$m_u g = 10 \ N ---(2)$

dividing equation 2 by equation 1

$\frac{m_ug}{m_wg} = \frac{10}{20}$

$\frac{m_u}{m_w} = \frac{1}{2}$

=> $m_u = 0.5 m_w$

Now since the volume of water and liquid displaced are the same then

$\rho _u = 0.5 \rho_w$

This because

$density = \frac{mass}{volume}$

So if volume is constant

mass = constant * density

Where $\rho_u$ is the density of the liquid

and $\rho_ w$ is the density of water which is a constant with a value $\rho_w = 1000 kg/m^3$

So

$\rho_u = 1000*0.5$

$\rho_u =500 kg /m^3$

7 0

2 years ago

When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 43.

zmey [24]

To solve this problem, we must take two important steps. First we will convert all the given units, to international system. Later we will define the torque, which is given as the product between the radius of application of the force and the Force acting on the body. Mathematically the latter is,

$\tau = r F$

Here,

r = Radius

F = Force

Now the units,

$r = 1.95cm = 1.95*10^{-2}m$

Replacing,

$\tau = (1.95*10^{-2})(43.5N)$

$\tau = 0.8483N\cdot m$

Therefore the torque that the muscle produces on the wrist is $0.85N\cdot m$

3 0

2 years ago

Nvm I dont need help anymore

pychu [463]

Answer:

no problem it's okay if you need any problem then ask

5 0

2 years ago

Why do plants need to obtain carbon atoms?

Firdavs [7]

Answer:

A) Plants use carbon to build glucose during photosynthesis.

Explanation:

Plants produce their food by the process of photosynthesis.

hope this helps :}

5 0

2 years ago

If a plane is moving at a constant velocity what is happening to the acceleration?

quester [9]

The plane is not accelerating.

Hope this helps!

4 0

2 years ago

Read 2 more answers