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Natalka [10]
3 years ago
6

A 3.0-A current is maintained in a simple circuit that consists of a resistor between the terminals of an ideal battery. If the

battery supplies energy at a rate of 25 W, how large is the resistance
Physics
1 answer:
harina [27]3 years ago
7 0

Answer:

R=2.78\ \Omega

Explanation:

Given that,

The current flowing in the circuit, I = 3 A

The power of the battery, P = 25 W

We need to find the resistance of the battery. We know that the power of the battery is given by the formula as follows :

P=I^2R

Put all the values to find R.

R=\dfrac{P}{I^2}\\\\R=\dfrac{25}{(3)^2}\\\\R=2.78\ \Omega

So, the resistance is equal to 2.78\ \Omega.

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Would you choose to have your genome sequenced to screen for diseases
leva [86]
Yes indeed.  Uh-huh, uh-huh.  I would <span>choose to have
my genome sequenced to screen for diseases. </span>
8 0
3 years ago
A radio telescope detects an incoming radio wave which has a power of 1.00 x 10-24 W. If this signal creates a potential of 1.00
soldier1979 [14.2K]

Answer:

Therefore, the number of electrons moving through the receiver circuit per second is 6250 electrons/s.

Explanation:

Given:

Power of radio wave, P = 1 × 10⁻²⁴ W

Potential of signal, V = 1 × 10⁻⁹ V

Solution:

Consider the number of electrons flowing through the receiver circuit per second be 'n'.

The current flowing through the circuit will be:

I = P/V

 = (1 × 10⁻²⁴ W)/(1 × 10⁻⁹ V)

 = 1 × 10⁻¹⁵ A

Then, the number of electrons moving through the receiver circuit can be  calculated as:

ne = I

where, e is charge on an electron

            I is current flowing through the circuit

Applying values in above equation we get:

n(1.6×10⁻¹⁹ C) = (1 × 10⁻¹⁵ A)

n = (1 × 10⁻¹⁵ A)/(1.6×10⁻¹⁹ C)

n = 6250 electrons/s

Therefore, the number of electrons moving through the receiver circuit per second is 6250 electrons/s.

Learn more about electron flow here:

<u>brainly.com/question/6531580</u>

#SPJ4

7 0
2 years ago
A radioactive isotope has a half-life of 5,000 years. A rock originally contained 16 grams of radioactive isotope, and now conta
mixas84 [53]

Answer:

10,000 years

Explanation:

Given that,

Half life of the radioactive isotope, t_{\frac{1}{2}} = 5000 years

Initial composition, N_0 = 16 grams

Final composition, N = 4 grams

We know that,

N=N_0\times (\dfrac{1}{2})^\frac{t}{t_\frac{1}{2}}}\\\\4=16(0.5)^\frac{t}{5000}}\\\\\dfrac{4}{16}=(0.5)^{\frac{t}{5000}}\\\\0.25=(0.5)^\frac{t}{5000}\\\\0.5^2=(0.5)^\frac{t}{5000}\\\\2=\dfrac{t}{5000}\\\\t=2\times 5000\\\\t=10000\ yrs

Therefore, the age of the rock is 10,000 years.

6 0
3 years ago
1.Particles are spaced the farthest apart in _____ and are the closest in ______. Select the answer that best completes the sent
Hunter-Best [27]

Answer:

gases; solids.

Explanation:

gases take up the most volume, meaning the particles are more spread apart (disorder, entropy, etc. if you are familiar with those). solids have the particles closer together, opposite of gases.

6 0
3 years ago
Read 2 more answers
3.
Ivan

Answer:

car B will be 30 Km ahead of car A.

Explanation:

We'll begin by calculating the distance travelled by each car. This is illustrated below:

For car A:

Speed = 40 km/h

Time = 3 hours

Distance =?

Speed = distance / time

40 = distance / 3

Cross multiply

Distance = 40 × 3

Distance = 120 Km

For car B:

Speed = 50 km/h

Time = 3 hours

Distance =?

Speed = distance / time

50 = distance / 3

Cross multiply

Distance = 50 × 3

Distance = 150 Km

Finally, we shall determine the distance between car B an car A. This can be obtained as follow:

Distance travelled by car B (D₆) = 150 Km

Distance travelled by car A (Dₐ) = 120 Km

Distance apart =?

Distance apart = D₆ – Dₐ

Distance apart = 150 – 120

Distance apart = 30 Km

Therefore, car B will be 30 Km ahead of car A.

7 0
3 years ago
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