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Korvikt [17]
3 years ago
5

Help? please and thank you​

Mathematics
1 answer:
11111nata11111 [884]3 years ago
8 0

Answer:

first one

relationship between base and perpendicular is

given by tan angle

tan x=P/h

remember perpendicular is opposite side of taken angle

tan x=13/8

<x=tàn-¹(13/8)=58.39°

for second one

relationship between base and hypotenuse is given by cos angle

cos G=b/h

cos G=24/32

<G=cos-¹(24/32)=41.4 is your answer

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Someone please help me im so confused​
ivann1987 [24]

Answer:

x=11

Step-by-step explanation:

5x+62=3x+47+37

5x+62=3x+84

2x=22

x=11

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3 years ago
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Answers please! I’m a bit confused
scoray [572]

Answer:

all work is shown and pictured

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How can you divide 3 4 by 65
Aleks04 [339]

Answer:

48 3/4

Step-by-step explanation:

65/1

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The population of a particular city is given by the function P(t) = 27,400(1.07)t, where t is the time in years and P(t) is the
otez555 [7]

Answer:

27,400 is the current population

7% is the rate of increase

The new size is:

  • 38,430 is the population if t is an exponent
  • 146,590 is t is NOT an exponent in the formula you typed

Step-by-step explanation:

To find the population in a future year, use the formula:

P(t) = 27,400(1.07)t

Substitute the value t=5 to find the population in 5 years.

P(t) = 27,400(1.07)t\\P(t) = 27,400(1.07)(5)\\P(t) = 146,590


Or if the equation is supposed to have t as an exponent then look below:

P(t) = 27,400(1.07)^t

Substitute the value t=5 to find the population in 5 years.

P(t) = 27,400(1.07)^t\\P(t) = 27,400(1.07)^(5)\\P(t) = 38,430

This formula is based off the standard formula A=A_0(1+r)^t so r, the rate is 1.07=1+0.07 so r is 7%.

A_0 is the starting population which is 27,400 here.

4 0
3 years ago
What is the solution set of the equation 30/x^2-9 +1=5/x-3
gizmo_the_mogwai [7]
\frac{30}{x^{2} - 9 + 1} = \frac{5}{x - 3} \\\frac{30}{x^{2} - 8} = \frac{5}{x - 3} \\5(x^{2} - 8) = 30(x - 3) \\5(x^{2}) - 5(8) = 30(x) - 30(3) \\5x^{2} - 40 = 30x - 90 \\5x^{2} + 50 = 30x \\5x^{2} - 30x + 50 = 0 \\5(x^{2}) - 5(6x) + 5(10) = 0 \\5(x^{2} - 6x + 10) = 0 \\\frac{5(x^{2} - 6x + 10)}{5} = \frac{0}{5} \\x^{2} - 6x + 10 = 0 \\x = \frac{-(-6) \± \sqrt{(-6)^{2} - 4(1)(10)}}{2(1)} \\x = \frac{6 \± \sqrt{36 - 40}}{2} \\x = \frac{6 \± \sqrt{-4}}{2} \\x = \frac{6 \± 2i}{2} \\x = 3 \± i \\x = 3 + i\ or\ x = 3 - i

The answer is D.
8 0
3 years ago
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