(A) Electricity and Magnetism

Two wheels having the same radius and mass rotate at the same angular velocity ((Figure 1) ). One wheel is made with spokes so n

liubo4ka [24]

Answer:

E. The wheel with spokes has about twice the KE.

See explanation in: https://quizlet.com/100717504/physics-8-mc-flash-cards/

6 0

3 years ago

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an 80.0 kg astronaut carrying a 15.0 kg tool kit is drifting away from the space station at a speed of 1.25 m/s. a) if she throw

jasenka [17]

The final speed of the astronaut at the space station is 0.36 m/s and the direction will be opposite to the direction of the tool kit thrown.

The mass of the astronaut = 80 kg

The mass of the tool kit = 15 kg

The speed of the space station = 1.25 m/s

The speed of the tool kit threw = 6 m/s

The final speed of the astronaut can be found using the conservation of momentum formula,

$\displaystyle m_{1}v_{f1} + m_{2}v_{f2} = m_{1}v_{i1} + m_{2}v_{i2}$

where m₁ is the mass of the astronaut

m₂ is the mass of the tool kit

$\displaystyle v_{i1}$ and $\displaystyle v_{i2}$ is the speed of the space station

$\displaystyle v_{f1}$ is the speed of the astronaut after throwing the toolkit

Let us substitute the known values in the above equation, we get

(80 x $\displaystyle v_{f1}$ ) + (15 x 6) = (80 x 1.25) + (15 x 1.25)

(80 x $\displaystyle v_{f1}$ ) + 90 = 100 + 18.75

80 x $\displaystyle v_{f1}$ = 118.75 - 90

80 x $\displaystyle v_{f1}$ = 28.75

$\displaystyle v_{f1}$ = 28.75 / 80

= 0.36 m/s

Therefore, the final speed of the astronaut is 0.36 m/s

By newton's third law, for every action, there will be an equal and opposite reaction. Thus, the direction of the astronaut's direction will be against the direction of the tool kit thrown.

Learn more about the conservation of momentum in

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5 0

1 year ago

A car with a mass of 1.50 X 10^3 kg starts from rest and accelerates to a speed of 18.0 m/s in 12.0 s. Assume that the force of

Serga [27]

The average power is 20.3 kW

Explanation:

First of all, we calculate the work done on the car: the work-energy theorem states that the work done on the car is equal to the change in kinetic energy of the car, so we have

$W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2$

where

W is the work done

$K_i, K_f$ are the initial and final kinetic energy of the car

$m=1.50\cdot 10^3 kg = 1500 kg$ is the mass of the car

u = 0 is the initial velocity

v = 18.0 m/s is the final velocity

Substituting,

$W=\frac{1}{2}(1500)(18)^2=2.43\cdot 10^5 J$

Now we can find the average power developed by the car's engine, which is given by

$P=\frac{W}{t}$

where

$W=2.43\cdot 10^5 J$ is the work done

t = 12.0 s is the time taken

Substituting,

$P=\frac{2.43\cdot 10^5 J}{12.0}=20,250 W = 20.3 kW$

Learn more about power:

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4 0

4 years ago

A person walks 25 m west and then 45 m at the angle of 60 degrees north of east what is the magnitude of the total displacement?

expeople1 [14]

To solve this question, we need to use the component method and split our displacements into their x and y vectors. We will assign north and east as the positive directions.

The first movement of 25m west is already split. x = -25m, y = 0m.

The second movement of 45m [E60N] needs to be split using trig.
x = 45cos60 = 22.5m
y = 45sin60 = 39.0m

Then, we add the two x and two y displacements to get the total displacement in each direction.

x = -25m + 22.5m = -2.5m
y = 0m + 39.0m

We can use Pythagorean theorem to find the total displacement.
d² = x² + y²
d = √(-2.5² + 39²)
d = 39.08m

And then we can use tan to find the angle.
inversetan(y/x) = angle
inversetan(39/2.5) = 86.3

Therefore, the total displacement is 39.08m [W86.3N]

8 0

4 years ago

Pleaseeeeeeeeee helpppppppppppppppp

Tju [1.3M]

I feel like it could be A

8 0

3 years ago