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3 years ago

Elana walked 12 miles. then she walked 1/4 that distance. how far did she walk all together. select all that apply.

Mathematics

1 answer:

Nezavi [6.7K]3 years ago

3 0

Answer:

c., d., f

Step-by-step explanation:

"elana walked 12 miles"

That is 12.

"then she walked 1/4 that distance"

That is 1/4 of 12 miles, so it is 1/4 * 12

She walked altogether

12 + 1/4 * 12 = 12 + 3 = 15

She walked altogether 15 miles.

a.12+1/4 = 12.25 which is not 15

b.12×1/4 = 3 which is not 15

c.12+1/4×12 = 12 + 3 = 15 which is correct

d.12(1+ 1/4) = 12(1.25) = 15 which is correct

e.12×3/4 = 9 which is not 15

f.12×5/4 = 15 which is correct

Answer: c., d., f

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Read 2 more answers

82, 62, 95, 81, 89, 51, 72, 56, 97, 98, 79, 85 order from least to greatest find the The median of the lower half of the data an

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Answer:

The median of the lower half of the data was determined to be 67 while the median of the upper half of the data was determined to be 92.

Step-by-step explanation:

Step 1: Order from least to greatest

51, 56, 62, 72, 79, 81, 82, 85, 89, 95, 97, 98

Step 2: Determine the median of the lower half of the data

There are 12 numbers which means that there is going to be 6 numbers on both sides of the data. So using the first 6 numbers we will be able to determine the median of the lower half of the data.

51, 56, 62, 72, 79, 81

Since there is an even amount of numbers, that means that we will need to find the middle between the 3rd and 4th number. We can do that by adding them up together and dividing by 2.

(62 + 72) / 2 = 67

Step 3: Determine the median of the upper half of the data

So using the first 6 numbers we will be able to determine the median of the upper half of the data.

82, 85, 89, 95, 97, 98

Since there is an even amount of numbers, that means that we will need to find the middle between the 3rd and 4th number. We can do that by adding them up together and dividing by 2.

(89 + 95) / 2 = 92

Answer: The median of the lower half of the data was determined to be 67 while the median of the upper half of the data was determined to be 92.

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