Answer:
1.69×10²⁹ molecules.
Explanation:
The following data were obtained from the question:
Mass of Ammonia (NH3) = 5.25 tons
Molecules of Ammonia (NH3) =.?
Next, we shall convert 5.25 tons to grams (g). This can be obtained as follow:
1 ton = 907184.74 g
Therefore,
5.25 ton = 5.25 ton × 907184.74 g / 1 ton
5.25 ton = 4762719.885 g
Therefore, 5.25 tons is equivalent to 4762719.885 g
Finally, we shall determine the number of molecules of ammonia, NH3 in 4762719.885 g. This can be obtained as follow:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of ammonia, NH3 also contains 6.02×10²³ molecules.
1 mole of ammonia, NH3 = 14 + (3x1) = 14 + 3 = 17 g
17 g of ammonia, NH3 contains 6.02×10²³ molecules.
Therefore, 4762719.885 g of ammonia, NH3 will contain = (4762719.885 × 6.02×10²³) / 17 = 1.69×10²⁹ molecules.
From the calculations made above,
5.25 tons (4762719.885 g) of ammonia, NH3 contains 1.69×10²⁹ molecules.
Burning fossil fuels release a lot of carbon dioxide which is a greenhouse gas which contributes to global warming. Also burning of fossil fuels causes a lot of air pollution. You can also describe in detail the effect of carbon dioxide on global warming in general
E = hc/(lamda)
The lamda symbol is wavelength, which this site does not have. I can represent it with an "x" instead.
Plancks constant, h = 6.626×10^-32 J·s
Speed of light, c = 3.00×10^8 m/s
The energy must be greater than or equal to 1×10^-18 J
1×10^-18 J ≤ (6.626×10^-32 J·s)*(3.0×10^8 m/s) / x
x ≤ (6.626×10^-32 J·s)*(3.0×10^8 m/s) / (1×10^-18 J)
x ≤ 1.99×10^-7 m or 199 nm
The wavelength of light must be greater than or equal to 199 nm
C. The answer is detroyed
That precipitation connects the hydrosphere with the geosphere by promoting erosion and weathering, surface processes that slowly break down large rocks into smaller ones. ... Both the geosphere and hydrosphere provide the habitat for the biosphere, a global ecosystem that encompasses all the living things on Earth.