The variable that is altered by the independent variable is called the dependent variable. the spectrum given out by the hypothetical unknown celestial object.
Name : Christopher Andre
Instructor name : Albert brown
Name of the lab : ELS Laboratory
The term electromagnetic spectrum refers to the range of electromagnetic radiation's frequencies, as well as the wavelengths and photon energies connected to each frequency.
By analyzing the absorption spectra of the planets and moons, the electromagnetic spectrum experiment seeks to identify the components that make up their atmospheres.
From below one hertz to over 1025 hertz, electromagnetic waves are included in the electromagnetic spectrum.
The wavelengths that correlate to the frequency range from tens of thousands of kilometers to a small portion of the size of an atomic nucleus.
Starting at the low frequency (long wavelength) end of the spectrum, each frequency band's electromagnetic waves are referred to by a variety of names.
Hence the dependent variable is the one that changes as a result of the independent variable.
Learn more about electromagnetic spectrum here
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Answer:
A drunk driver's car travel 49.13 ft further than a sober driver's car, before it hits the brakes
Explanation:
Distance covered by the car after application of brakes, until it stops can be found by using 3rd equation of motion:
2as = Vf² - Vi²
s = (Vf² - Vi²)/2a
where,
Vf = Final Velocity of Car = 0 mi/h
Vi = Initial Velocity of Car = 50 mi/h
a = deceleration of car
s = distance covered
Vf, Vi and a for both drivers is same as per the question. Therefore, distance covered by both car after application of brakes will also be same.
So, the difference in distance covered occurs before application of brakes during response time. Since, the car is in uniform speed before applying brakes. Therefore, following equation shall be used:
s = vt
FOR SOBER DRIVER:
v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s
t = 0.33 s
s = s₁
Therefore,
s₁ = (73.33 ft/s)(0.33 s)
s₁ = 24.2 ft
FOR DRUNK DRIVER:
v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s
t = 1 s
s = s₂
Therefore,
s₂ = (73.33 ft/s)(1 s)
s₂ = 73.33 ft
Now, the distance traveled by drunk driver's car further than sober driver's car is given by:
ΔS = s₂ - s₁
ΔS = 73.33 ft - 24.2 ft
<u>ΔS = 49.13 ft</u>
Lets say sphere 1 has a charge of 12 + and sphere 2 has a charge of 0 +. After they are touched Sphere 1 becomes 6 + and sphere 2 6 +. So 6 - 12 = a change of 6 -, while 6 - 0 = a change of 6 + Therfore,
Answer: The sign of the charge change / transfered are opposites.
