Answer:
Option D. 5.45 Ω
Explanation:
From the question given above, the following data were obtained:
Resistance 1 (R₁) = 10 Ω
Resistance 2 (R₂) = 20 Ω
Resistance 3 (R₃) = 30 Ω
Voltage (V) = 120 V
Equivalent resistance (R) =?
The equivalent resistance can be obtained as follow:
1/R = 1/R₁ + 1/R₂ + 1/R₃
1/R = 1/10 + 1/20 + 1/30
Find the least common multiple (lcm) of 10, 20 and 30. The result is 60
Divide 60 by each of the denominators and multiply by their numerators respectively. We have:
1/R = (6 + 3 + 2)/60
1/R = 11/60
Invert
R = 60/11
R = 5.45 Ω
Thus, the equivalent resistance in the circuit is 5.45 Ω
Answer: the two states that are fluid are;-
<u>#{1} liquid</u>
<u>#{2} gas </u>
Explanation:
as we know that there are mainly three states of substance
but among them only two of them can fluid and takes the shape of the container that are liquid and gas
Since the factory will be producing 100,000 kilograms of cement, using the relation 1000 kg of cement = 900 kg of CO2, then the factory will be emitting 90,000 kg of CO2 at the same time. To counteract the emission, a tree can remove 6 kg of CO2 per day. Dividing 90,000 kg by 6 kg to know the number of trees, we need 15000 trees to counter the emission. Since 1 acre of land holds 200 trees, we need 75 acres of land to hold the 15000 trees.
100/2.5 is 40.
40 is the energy that is being produced
Answer:
0.34s, 8.5m,31.89m
Explanation:
The above motion defines a projectile motion.
Now the athletes lands on a cliff 30° to the horizontal this means the velocity at that point would be 25m/s cos30°
Now from Newton's law of motion.
The body would be decelerating so,
V = u - gt
Where u is initial velocity and v is final velocity. g is acceleration of free fall due to gravity.
Hence,
V-U/ -g = t
Hence 25cos30 - 25/ -9.8 = 0.34s.
2.Now the length of the jump is defined as the total horizontal distance which is marked off by the horizontal velocity and time taken for take off and landing.
Hence Distance,S = u × t
25 ×0.34 =8.5m.
3. The maximum height is defined that at that point the Final velocity is 0m/s
Now the initial velocity is 25m/s
From Newton's law that;
V2= U2 -2gH; where U and V are initial and final velocity and H is height.
Hence H = V2-U2/-2g
=(0)^2- (25)^2/ -2×9.8
= -625/-19.6 =31.89m