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LekaFEV [45]
2 years ago
7

Deriving projectile motion formulas

Physics
1 answer:
kipiarov [429]2 years ago
6 0

Answer:

Projectile motion formula or equations derived (In Tabular format)Motion Path equation:


y = (tanθ) x – (1/2) g . x2/(V0 cosθ)2

Explanation:

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A ball is spun around in circular motion such that it completes 50 rotations in 25 s. What is the frequency of its rotation? 2.
Elis [28]

Answer:

1. f = 2 Hz

2. f = 0.011 Hz

3. f = 0.067 Hz

4. t = 4 s

Explanation:

1. The frequency of rotation is given by:

f = \frac{\omega}{2\pi}

Where:

ω: is the angular speed = 50 rotations (revolutions) in 25 s.

We need to convert the units of ω.

\omega = \frac{50 rev}{25 s}*\frac{2\pi rad}{1 rev} = 4\pi rad/s

Now, the frequency is:

f = \frac{4\pi rad/s}{2\pi} = 2 Hz

2. The frequency is:

We know:

5 laps = 5 revolutions

t: time = 450 s

f = \frac{\omega}{2\pi} = \frac{\frac{5 rev}{450 s}*\frac{2\pi rad}{1 rev}}{2\pi} = 0.011 Hz    

3. The frequency of the pendulum is:

f = \frac{\omega}{2\pi} = \frac{\frac{1 rev}{15 s}*\frac{2\pi rad}{1 rev}}{2\pi} = 0.067 Hz

4. We have:

θ: number of revolutions = 48 rev

f = 12 Hz

t =?

The time can be calculated as follows:

f = \frac{\omega}{2\pi} = \frac{\theta}{2\pi t}

t = \frac{\theta}{2\pi f} = \frac{48 rev*\frac{2\pi rad}{1 rev}}{2\pi*12 Hz} = 4 s

I hope it helps you!

4 0
3 years ago
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