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Dmitry_Shevchenko [17]
3 years ago
12

please help please plase please please please please please please please please please please please please please why is pleas

e spelled like please

Mathematics
2 answers:
Masteriza [31]3 years ago
5 0
The answer to the question is D
coldgirl [10]3 years ago
3 0
Most likely A or B I believe it’s A

God bless!! <3
You might be interested in
|(1)
Yanka [14]
So first you would divide 1950/6 to find the amount for one year of their age.
Then you would multiply that by the ages, which should get you 4 numbers, then you all those numbers together. Try 9750.
3 0
3 years ago
1) Write a system of equations to describe the situation below, solve using any method, and
Aloiza [94]
This situation can be represented by

y = 33x + 223

y = 32x + 239

I still like substitution, so let’s plug in 33x + 223 into the second equation

33x + 223 = 32x + 239

Move the terms into appropriate sides

33x - 32x = 239 - 223

Combine like terms

x = 16

Then plug in x for any equation

y = 32(16) + 239

y = 751

Erin will have to swim 16 laps for a total of 751 meters
7 0
3 years ago
Question
Gnoma [55]

Given parameters:

     y varies directly as w;

   This interpreted implies that as y increases, we increases by a certain factor or amount;

    So,  y ∝  w

           y  = kw

   where k is the constant of proportionality

Now, given that y  = 8 and w = 2

Input in the equation to solve for k;

               8 = k x 2

     Solving k gives, k = 4

Now to the second part,

          if v is directly proportional to w;

                v  = k w

        So   v  = 4w

The equation that relates v to w is v = 4w

3 0
3 years ago
What is the answer plz 2+8-4•7
iris [78.8K]
2+8-4x7
2+8-28
10-28=-18
6 0
4 years ago
Read 2 more answers
Hey can anyone pls answer these math problems!!
Zepler [3.9K]

Answer:

1={5 and 3} 2={0} 3={0.209 and 4.791} 4={-3 and 4} 5={1 and 9} 6={-4.303 and -0.697}

Step-by-step explanation:

Your probably confused on what a, b, and c means.

The problems are written like this.

ax^2+bx+c=0

That formula finds the zeros.

For example 1:

x^2-8x+15=0\\ax^2-bx-c\\a=1\\b=-8\\c=15

Then use the formula

x=\frac{-b+-\sqrt{b^2-4ac} }{2a} \\\\x=\frac{-(-8)+-\sqrt{-8^2-4(1)(15)} }{2} \\x=\frac{8+-\sqrt{64-60} }{2} \\\\x=\frac{8+-2}{2}\\

If plus then 5, if minus then 3

CHECK:

x^2-8x+15=0\\5^2-8(5)+15=0\\25-40+15=0\\0=0\\3^2-8(3)+15=0\\9-24+15=0\\0=0

Hope this helps you understand how to do this by yourself.  Now to do the rest ;-;

5 0
2 years ago
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