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Zarrin [17]
3 years ago
12

Whats 2+2 lollololololololololololololololololololo

Mathematics
1 answer:
ra1l [238]3 years ago
5 0

Answer:

4ssssssssssssssssssssssssssss

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PolarNik [594]
The correct answer would most likely be option C. This is because the lowest tip was on 5, thus we can eliminate B and D.

And during this time the slope almost remained stationary, minimal change.







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3 years ago
If x=4cos(2t) and y=4sin(2t), what is the parameter of these equations
kobusy [5.1K]

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y=√(4+x)(4−x)

Step-by-step explanation:

7 0
3 years ago
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Answer:5

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7

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2 years ago
Translate this sentence into an equation.<br> 45 is the sum of 19 and Victor's score
Alex17521 [72]

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5 0
3 years ago
A sprinter who weighs 706 N runs the first 5.5 m of a race in 1.6 s, starting from rest and accelerating uniformly. What are the
zhenek [66]

Answer:

(a) Speed = 6.875 m/s

(b) Kinetic Energy = 1.70 kJ

(c) Average power =  1.06 kW

Step-by-step explanation:

Given:

d = 5.5 m

t = 1.6 s

W = 706 N

Part (a)

Using the equation of motion with the assumption of zero initial speed:

d = \frac{1}{2} ({v-0})t

5.5= \frac{1}{2} (1.6v)

The speed of the sprinter then become:

v = 6.875 m/s

Part (b)

Convert the weight of the sprinter to mass:

m = \frac{w}{g}

m = \frac{706}{9.8}

m = 72 kg

KE (Kinetic Energy) can then be calculated as:

KE = \frac{1}{2} mv^{2}

KE = \frac{1}{2} (72)(6.875)^{2}

KE = 1701.56 J = 1.70 kJ

Part (c)

The change of the kinetic energy is equivalent to the work done by the sprinter. The average power P is the rate of the work done and can be calculated as

P = \frac{KE}{t} \\\

P = \frac{1701.56}{1.6}

P = 1063.48 W = 1.06 kW

5 0
3 years ago
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