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Ira Lisetskai [31]

3 years ago

5

How are independent and dependent variables related?

1 answer:

shtirl [24]3 years ago

3 0

They are pretty much the cause and effect. The independent variable that is being changed in the experiment, so it is the cause. The dependant variable is the result of change the independant variable, so the effect.

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I don’t understand this question and need help!!

Dafna1 [17]

Medium about 3 second? Not sure lol just need more points honestly lol

6 0

1 year ago

How does cold water affect the speed of dissolving?

sineoko [7]

Answer:

Anything that can be done to increase the frequency of those collisions and/or to give those collisions more energy will increase the rate of dissolving.

Explanation:

depended on the temperature

4 0

2 years ago

From the value Kf=1.2×109 for Ni(NH3)62+, calculate the concentration of NH3 required to just dissolve 0.016 mol of NiC2O4 (Ksp

Nina [5.8K]

<u>Answer:</u> The concentration of $NH_3$ required will be 0.285 M.

<u>Explanation:</u>

To calculate the molarity of $NiC_2O_4$ , we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of $NiC_2O_4$ = 0.016 moles

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M$

For the given chemical equations:

$NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}$

$Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9$

Net equation: $NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?$

To calculate the equilibrium constant, K for above equation, we get:

$K=K_{sp}\times K_f\\K=(4.0\times 10^{-10})\times (1.2\times 10^9)=0.48$

The expression for equilibrium constant of above equation is:

$K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}$

As, $NiC_2O_4$ is a solid, so its activity is taken as 1 and so for $C_2O_4^{2-}$

We are given:

$[[Ni(NH_3)_6]^{2+}]=0.016M$

Putting values in above equations, we get:

$0.48=\frac{0.016}{[NH_3]^6}}$

$[NH_3]=0.285M$

Hence, the concentration of $NH_3$ required will be 0.285 M.

7 0

2 years ago

List 3 elements that have similar properties or reactivity. Justify your answer with reasoning.

Rus_ich [418]

Answer:

Lithium, Potassium and Calcium

Explanation:

Because they are all in group one of the periodic table

7 0

2 years ago

Given a 240.0 g sample of sulfur trioxide (MM = 80.1 g/mol),

labwork [276]

Answer:

2 mol of SO3 produces 1 mol O2

3 mol SO3 produces 3/2 mol of O2

so O2 produced = 1.5(32) =48 gm

Explanation:

8 0

2 years ago