Given: an n-gon
Prove: The sum of the measures of the interior angles is 180(n – 2)°.
Complete the missing parts of the paragraph proof.
We are given an n-gon, which has n sides and n vertices.
Answers:
1. If we choose one of the vertices, we can draw <u>n-3</u> diagonals.
2. These diagonals form <u>n-2</u> triangles.
3. The sum of the interior angle measures of a triangle is <u>180</u> degrees.
4. <u>n – 2</u> triangles would have an interior angle measure sum of <u>180</u> degrees.
5. Therefore, the sum of the measures of the interior angles of an n-gon is 180(n – 2)°.
H, r
Surface Area = 2πrh
If the h, is now h/3 and the r, now r/3
Surface Area = <span>2π*r/3*h/3
= </span><span>2πrh/9
</span><span>
The modified surface area is reduced by 9 times.
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3: terms/ 12, 8r, -3, s, -5, 15t coefficients/ 8r, 1s, 15t
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Answer:
Associative property of addition.
