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leva [86]
3 years ago
9

Ivan exerts 20 N of force to lift a basket 2 m. He then carries the basket 5 m across a room to place it on a shelf. Ivan does w

ork when he . The amount of work he does is .
Physics
2 answers:
amid [387]3 years ago
7 0
A) <span>Ivan does work when he lifts the basket

B) Work = Force * displacement 
W = 20 * 2
W = 40 Joules

So, The Amount of work he does is 40 Joules

Hope this helps!</span>
Cerrena [4.2K]3 years ago
5 0

Explanation :

It is given that,

Force acting on Ivan,  F=20\ N

Height of the basket above the ground, s = 2 m

Work done in this case would be :

 W=Fs\ cos\theta

Where

\theta is the angle between the force and the displacement and it is equal to 0.

So, W=20\ N\times 2\ m

W=40\ J

Ivan does work when he lifts the basket and it is equal to 40 J.

When he carries the basket 5 m across a room to place it on a shelf, then his weight is acting vertically downwards. The angle between the force and the displacement is now 90.

So, the work done he does is 0.                      

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3 years ago
By what factor must the amplitude of a sound wave be decreased in order to decrease the intensity by a factor of 2?
alina1380 [7]
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sound intensity = sound power / (4 pi R2<span>)
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4 0
3 years ago
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How many drops of water are in a 1.0 L bottle? (Hint: Start by estimating the diameter of a drop of water.)
o-na [289]

Answer:

N = 2000 drops approx with 1 cm diameter each

Explanation:

Let the diameter of one drop is 1 cm

so volume of one drop is given by

V = \frac{1}{6}\pi d^3

now we have

V = \frac{1}{6}\pi(0.01)^3

V = 0.53 \times 10^{-6} m^3

now in 1L of liquid let say N drops are there

so we have

1L = 10^{-3} m^3

now we have

N = \frac{10^{-3}}{0.53 \times 10^{-6}}

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nasty-shy [4]

<u>Answer:</u> The ball is travelling with a speed of 5.5 m/s after hitting the <u>bottle.</u>

<u>Explanation:</u>

To calculate the speed of ball after the collision, we use the equation of law of conservation of momentum, which is given by:

m_1u_1+m_2u_2=m_1v_1+m_2v_2

where,

m_1,u_1\text{ and }v_1 are the mass, initial velocity and final velocity of ball.

m_2,u_2\text{ and }v_2 are the mass, initial velocity and final velocity of bottle.

We are given:

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(0.4\times 18)+(0.2\times 0)=(0.4\times v_1)+(0.2\times 25)\\\\v_1=5.5m/s

Hence, the ball is travelling with a speed of 5.5 m/s after hitting the bottle.

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