To calculate the pH of a solution that has a [H3O+] of 7.22x10^-7. You would do the following
pH=-log[H3O+]
pH=-log[7.22x10^-7]
pH=?
A) Head to tail joining of monomers. :) (confirmed correct answer, I took the test)
Answer:
HBr + KOH -> KBr + H₂O
Explanation:
Acid-base reactions always produce a salt [KBr] and water [H₂O].
