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Considering the ideal gas law and the definition of molar mass, the molar mass of the sample of gas is 9.17 .
An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where:
- P is the gas pressure.
- V is the volume that occupies.
- T is its temperature.
- R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.
- n is the number of moles of the gas.
The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
<h3>Molar mass of the sample of gas</h3>In this case you know:
- P= 0.980 arm
- V= 1.20 L
- T= 287 K
- R= 0.082
- n= ?
Replacing in the ideal gas law:
0.980 atm× 1.20 L= n× 0.082× 287 K
Solving:
(0.980 atm× 1.20 L)÷ (0.082× 287 K)= n
<u><em>0.04997 moles= n</em></u>
On the other hand, you know that the<u><em> mass of the sample of gas</em></u> is <u><em>0.458 grams</em></u>. Replacing in the definition of molar mass:
Solving:
<u><em>molar mass= 9.17 </em></u>
Finally, the molar mass of the sample of gas is 9.17 .
Learn more about
molar mass:
ideal gas law:
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Solution:
a) By stoichoimetry If 6 moles of gives 4 mole of
, then 22 moles of
will give:
moles of
b) If 6 moles of reacts with one mole of
, then 22 moles of
will react :
moles of
Moles of left after the reaction =
moles.
c) 0 Moles of , since it is present in less amount it will get completely consumed in the reaction. Hence, it is limiting reagent.
Hope this helps :) I didn’t know how to write subscripts so I wrote it down on some paper.
