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2 years ago

Plz answer quickly with explanations. .....

Chemistry

1 answer:

sattari [20]2 years ago

5 0

Answer:

It would be gas b. The gas you are talking about is carbon dioxide and for the reaction to work the gas needs to be bubbled through into the lime water.

Explanation:

The carbon dioxide reacts with lime water which is a solution of calcium hydroxide to form the white precipitate of calcium carbonate CaCO 3.

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As carbon dioxide (CO2) changes from its solid state to gaseous state, what happens to the energy and motion of the particles?

SVEN [57.7K]

1) As carbon dioxide changes from solid state to gaseous state, the particles gain energy and move faster.

The molecule of CO2 gain energy which results in greater separation of each other and freer and faster movement

2) When a substance undergoes a change of state its mass does not change

8 0

2 years ago

HELP!? #20 Which type of bond is formed when bases pair in DNA? ionic bond covalent bond coordinate bond hydrogen bond

lesya [120]

hydrogen bond, nucleotides in a base pair complement each other which means their shape allows them to bond together with hydrogen bonds.

3 0

2 years ago

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Hydrogen sulfide decomposes according to the following reaction, for which Kc=9.30E-8 at 700 degrees Celsius. 2 H2S(g) --> 2

Svetlanka [38]

Answer: The equilibrium concentration of $H_2(g)$ at 700 degrees Celsius is 0.0012 M

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_c
$

Moles of $H_2S$ = 0.29 mole

Volume of solution = 3.0 L

Initial concentration of $H_2S$ = $\frac{0.29mol}{3.0L}=0.097M$

The given balanced equilibrium reaction is,

$2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)$

Initial conc. 0.097 M 0M 0M

At eqm. conc. (0.097-2x) M (2x) M (x) M

The expression for $K_c$ is written as:

$K_c=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}$

$K_c=\frac{(2x)^2\times x}{(0.097-2x)^2}$

$9.30\times 10^{-8}=\frac{(2x)^2\times x}{(0.097-2x)^2}$

$x=0.00060$

Equilibrium concentration of $[H_2]$ = 2x= $2\times 0.00060=0.0012M$

6 0

2 years ago

Does H₂ have a coefficient?

Digiron [165]

No it does not have a coefficient.

8 0

3 years ago

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Indicate whether the following balanced equations involve oxidation-reduction. Check all that apply. Check all that apply. 2H2SO

guapka [62]

Answer : The balanced equations involve oxidation-reduction are:

(a) $2H_2SO_4(aq)+2NaBr(s)\rightarrow Br_2(l)+SO_2(g)+Na_2SO_4(aq)+2H_2O(l)$

(b) $3SO_2(g)+2HNO_3(aq)+2H_2O(l)\rightarrow 3H_2SO_4(aq)+2NO(g)$

(c) $NaI(aq)+3HOCl(aq)\rightarrow NaIO_3(aq)+3HCl(aq)$

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

(a) The given chemical reaction is:

$2H_2SO_4(aq)+2NaBr(s)\rightarrow Br_2(l)+SO_2(g)+Na_2SO_4(aq)+2H_2O(l)$

This reaction involve oxidation-reduction reaction because the oxidation state bromine changes from (-1) to (0) which shows oxidation and sulfur changes from (+6) to (+4) which shows reduction.

(b) The given chemical reaction is:

$3SO_2(g)+2HNO_3(aq)+2H_2O(l)\rightarrow 3H_2SO_4(aq)+2NO(g)$

This reaction involve oxidation-reduction reaction because the oxidation state sulfur changes from (+4) to (+6) which shows oxidation and nitrogen changes from (+5) to (+2) which shows reduction.

(c) The given chemical reaction is:

$NaI(aq)+3HOCl(aq)\rightarrow NaIO_3(aq)+3HCl(aq)$

This reaction involve oxidation-reduction reaction because the oxidation state iodine changes from (-1) to (+5) which shows oxidation and chlorine changes from (+5) to (-1) which shows reduction.

(d) The given chemical reaction is:

$PBr_3(l)+3H_2O(l)\rightarrow H_3PO_3(aq)+3HBr(aq)$

This reaction does not involve oxidation-reduction reaction because the oxidation state of element present on reactant and product side are same.

3 0

2 years ago