a. Let 
be a random variable representing the weight of a ball bearing selected at random. We're told that 
, so
where 
. This probability is approximately
b. Let 
be a random variable representing the weight of the 
-th ball that is selected, and let 
be the mean of these 4 weights,
The sum of normally distributed random variables is a random variable that also follows a normal distribution,
so that
Then
c. Same as (b).
Answer:
For, "x" greater than 34, the perimeter of the picture frame greater than 152 inches
Solution:
Let "x" be the width of the frame
Given that, The length of a picture frame is 8 inches more than the width
Therefore,
Length = width + 8
Length = x + 8
The perimeter of rectangle is given by formula:
Perimeter = 2(length + width)
Substituting the values we get,
Perimeter = 2(x + 8 + x)
Perimeter = 2(2x + 8)
Perimeter = 4x + 16
The perimeter of the picture frame greater than 152 inches
Perimeter > 152
Therefore, for, "x" greater than 34, the perimeter of the picture frame greater than 152 inches
Step-by-step explanation:
search it up
Answer:
y=1
x=7/4
Step-by-step explanation:
4x + 5y = 12
3x + 4y = 9.25
4x + 5y = 12
12x + 16y =37
-12x -15 y =-36
12x + 16y =37
y=1
x=7/4
