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abruzzese [7]
3 years ago
8

A sample of gas contains 6.25 × 10-3 mol in a 500.0 mL flask at 265°C.

Chemistry
1 answer:
garik1379 [7]3 years ago
8 0

Answer:

The pressure of gas in kilopascals is 55.9

Explanation:

variables given :

volume

temperature

moles  

unknown variables :

pressure

Select the correct algebraic form for the equation to be used for this calculation.

p= nRT/V

Solve the problem for the pressure of oxygen.

Answer:

<h3> <u>55.9 kPa</u></h3>
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Which stage of the scientific process enables a scientist to check the work of other
blsea [12.9K]

Answer:

The answer to this would be communicating.

Explanation:

A scientist would be communicating to his or her fellow colleagues and sharing to them his or her idea.

Hope you find this answer helpful! :)

3 0
3 years ago
A 2.00-mol sample of hydrogen gas is heated at constant pressure from 294 K to 414 K. (a) Calculate the energy transferred to th
Furkat [3]

Answer:

a) The energy transferred is 6.91 kJ

b) The internal energy is 4.90 kJ

c) The work done on the gas is - 2.01 kJ

Explanation:

Step 1: Data given

Number of moles of hydrogen gas = 2.00 moles

Pressure = constant

Temperature is heated from 294 K to 414 K

Molar heat capacity of hydrogen gas = 28.8 J/mol*K

Step 2: Calculate the energy transferred to the gas by heat.

Q = n* Cp * ΔT

⇒with Q =the energy transferred

⇒with n = the number of moles = 2.00 moles

⇒with Cp = the Molar heat capacity of hydrogen gas = 28.8 J/mol*K

⇒ with ΔT = Temperature 2 - Temperature 1 = 414 - 294 = 120K

Q = 2.00 * 28.8 * 120

Q = 6912 J = 6.91 kJ

Step 3: Calculate the increase in its internal energy.

ΔEint = n*Cv*ΔT

⇒with ΔEint = the increase in its internal energy.

⇒with n = the number of moles = 2.00 moles

⇒with Cv = The constant volume = 20.4 J/mol*K

⇒with  ΔT = Temperature 2 - Temperature 1 = 414 - 294 = 120K

ΔEint = 2.00 * 20.4 * 120

ΔEint =4896 J = 4.90 kJ

Step 4: Calculate the work done on the gas.

Work done on the gas = -Q + ΔEint

W = -6.91 kJ + 4.90 kJ

W = -2.01 kJ

6 0
3 years ago
Consider 10.0 g of helium gas (He) in a rigid steel container. If you add 10.0 g of neon gas (Ne) to this container, which of th
Norma-Jean [14]

Answer: (e) The pressure in the container increases but does not double.

Explanation:

To solve this, we need to first remember our gas law, Boyle's law states that the pressure and volume of a gas have an inverse relationship. That is, If volume increases, then pressure decreases and vice versa, when temperature is held constant. Therefore, increasing the volume in this case does not double the pressure owning to out gas law, but an increase in pressure would be noticed if temperature is constant

6 0
3 years ago
Explain why we must balance all chemical equations
enyata [817]

Answer:

The chemical equation needs to be balanced so that it follows the law of conservation of mass.

Explanation:

3 0
3 years ago
Read 2 more answers
Some chemical bonds are considered molecules while others are considered compounds.
taurus [48]

Molecule is the general term used to describe any atoms that are connected by chemical bonds. Every combination of atoms is a molecule. A compound is a molecule made of atoms from different elements. All compounds are molecules, but not all molecules are compounds.

One example of a molecule is Cl_2 (chlorine).

Examples of a compound is NaCl (sodium chloride) or H_2O\\ (water)

5 0
3 years ago
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