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kicyunya [14]
3 years ago
11

How many moles in 200 grams of Br

Chemistry
1 answer:
saveliy_v [14]3 years ago
6 0
2.5030036043252 moles.
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Which best describes the effect of jj Thomson discovery
beks73 [17]
JJ Thomson discovered electrons using the cathode ray. Electrons are negatively charged particles that orbit around the nucleus of an atom. Finding out that there was a negative charge to balance out the positive charge. This later helped develop Hund's Rule and the Pauli Exclusion Principle.
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3 years ago
What is the concentration of hydrogen ions in a solution of KOH with a pOH of 1.72?
bezimeni [28]

Answer:

[h+]= 5.25e-13

Explanation:

pH= 14-1.72= 12.28

[h+]= 5.25e-13

3 0
3 years ago
Bruh i need help and someone just used the last one for points plz help​
ankoles [38]

Answer: 5000

Explanation:

6 0
3 years ago
If a 60-g object has a volume of 30 cm3, what is its density? 2 g/cm3 0.5 cm3/g 1800 g * cm3 none of the above
jasenka [17]

Answer : The density of an object is, 2g/cm^3

Solution : Given,

Mass of an object = 60 g

Volume of an object = 30cm^3

Formula used :

\text{Density of an object}=\frac{\text{Mass of an object}}{\text{Volume of an object}}

Now put all the given values in this formula, we get the density of an object.

\text{Density of an object}=\frac{60g}{30cm^3}=2g/cm^3

Therefore, the density of an object is, 2g/cm^3

6 0
3 years ago
A 12.5 g sample of granite initially at 82.0 oc is immersed into 25.0 g of water that is initially at 22.0 oc. what is the final
Paraphin [41]

The amount of heat lost by granite is equal to the amount of heat gained by water. Therefore their change in enthalpies must be equal. The opposite in sign means that one is gaining while the other is losing

ΔH granite = - ΔH water

ΔH is the change in enthalpy experienced by a closed object as it undergoes change in energy. This is expressed mathematically as,

ΔH = m Cp (T2 – T1)

Given this information, we can say that:

12.5 g * 0.790 J / g ˚C * (T2 – 82 ˚C) = - 25.0 g * 4.18 J / g ˚C * (T2 – 22 ˚C)

9.875 (T2 – 82) = 104.5 (22 – T2)

9.875 T2 – 809.75 = 2299 – 104.5 T2

114.375 T2 = 3108.75

T2 = 27.18 ˚C

The temperature of 2 objects after reaching thermal equilibrium is 27.18 ˚<span>C.</span>

7 0
3 years ago
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