If you have 5 grams of carbon and 6 grams of hydrogen and you want to make methane, what is reaction limiting?

1 answer:

5 0

Methane's formula is CH4 I don't get the question but if those are the quantities of 1 of those metals, that means that you don't have enough grams of carbon. You will need 5g x 4 = 20grams of carbon.

Hope that's what you were looking for.

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Why do magnesium, phosphorus, and zinc exhibit slightly higher first ionization energies than the general trend within each of t

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Because they are farther across the periodic table

8 0

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kicyunya [14]

The molar mass of a, b and c at STP is calculated as below

At STP T is always= 273 Kelvin and ,P= 1.0 atm

by use of ideal gas equation that is PV =nRT
n(number of moles) = mass/molar mass therefore replace n in the ideal gas equation

that is Pv = (mass/molar mass)RT
multiply both side by molar mass and then divide by Pv to make molar mass the subject of the formula

that is molar mass = (mass x RT)/ PV

density is always = mass/volume

therefore by replacing mass/volume in the equation by density the equation
molar mass=( density xRT)/P where R = 0.082 L.atm/mol.K

the molar mass for a
= (1.25 g/l x0.082 L.atm/mol.k x273k)/1.0atm = 28g/mol

the molar mass of b
=(2.86g/l x0.082L.atm/mol.k x273 k) /1.0 atm = 64 g/mol

the molar mass of c

=0.714g/l x0.082 L.atm/mol.K x273 K) 1.0atm= 16 g/mol

therefore the
gas a is nitrogen N2 since 14 x2= 28 g/mol
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gas c = methaneCH4 since 12+(1x4) = 16 g/mol

8 0

3 years ago

The mass of an electron is 9.11× 10–31 kg. What is the uncertainty in the position of an electron moving at 2.00 × 106 m/s with

Kruka [31]

Just use the Heisenberg Uncertainty principle:

ΔpΔx = h/2*pi 

Δp = the uncertainty in momentum 
Δx = the uncertainty in position 
h = 6.626e-34 J s (plank's constant) 

Hint: 

to calculate Δp use the fact that the uncertainty in the momentum is 1% (0.01) so that 

Δp = mv*(0.01) 

m = mass of electron 
v = velocity of electron 

Solve for Δx 

Δx = h/(2*pi*Δp) 

And that is the uncertainty in position.

6 0

4 years ago

What is the change in density if a sample goes from 3.21 g/L to 5.43 g/mL?

Step2247 [10]

Answer:

$\Delta \rho =2.22 g/mL$

Explanation:

Hello,

In this case, since a change in science is widely known to be considered as a subtraction between the the final and initial values of two measured variables and is represented via Δ, here the final density is 5.43 g/mL and the initial one was 3.21 g/mL, therefore, the change in density is:

$\Delta \rho=\rho _f-\rho _i\\ \\\Delta \rho=5.43g/mL-3.21g/mL\\\\\Delta \rho =2.22 g/mL$

Best regards.

3 0

3 years ago

The decomposition of nitrogen dioxide is described by the following chemical equation: Suppose a two-step mechanism is proposed

Mandarinka [93]

Answer:

first step

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second step

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first step

NO2(g) ------------------------------------> NO(g) + O(g)

second step

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