Answer:
pH = 8.34
Explanation:
The equilbriums of the amphoteric HCO₃⁻ (Ion of NaHCO₃) are:
H₂CO₃ ⇄ <em>HCO₃⁻</em> + H⁺ Ka1 <em>-Here, HCO₃⁻ is acting as a base-</em>
<em>HCO₃⁻</em>⇄ CO₃²⁻ + H⁺ Ka2 <em>-Here, is acting as an acid-</em>
Where Ka1 = 4.3x10⁻⁷ and Ka2 = 4.8x10⁻¹¹. As pKa = -log Ka:
pKa1 = 6.37; pKa2 = 10.32
As the pH of amphoteric salts is:
pH = (pKa1 + pKa2) / 2
<h2>pH = 8.34</h2>
Answer: <span>Molecular geometry around each carbon atom in a saturated hydrocarbon is
Tetrahedral.
Explanation: </span> In saturated hydrocarbons (-CH₂-) the central atom (
carbon) is bonded to either three or two hydrogen atoms and one or two carbon atoms. So, the central atom is having four electron pairs and all pairs are bonding pairs and lacks any lone pair of electron. According to
Valence Shell Electron Pair Repulsion (VSEPR)
Theory the central atom with four bonding pair electrons and zero lone pair electrons will attain a
tetrahedral geometry with
bond angles of 109°.
Answer:
here it is
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