Remember, half of the energy in an EM wave is in the E field, the rest is in the B field.
Thus, multiply E field energy by 2.
To calculate the energy of the wave you must then use the following equation: W = A*t*c*2*(1/2*E^2*Eo). Where, A = Area, t = time, c = speed of light (which is a constant), E = Electric field, E0 = vacuum permittivity (8.85*10^-12 Nm^2/C^2). Substituting W =(0.320)*(26)*(3*10^8)*(2)*((1/2)*(1.95*10^-2)^2*(8.854*10^-12)) = 8.40*10^-6 J
Answer: the velocity of the center of mass of the two block is v.
Explanation:
Hi, to answer this question we have to apply the next formula:
vcm = [ m1v1 + m2v2] / (m1+m2)
Where:
vcm =velocity of the center of mass
m1 = mass 1 , m2 = mass2
v1 = velocity 1; v2= velocity 2
Replacing with the values given:
vcm = ( 2(4v) - 3v) / (2+3) = (8v-3v) /5 = 5v/5 = v
The velocity of the center of mass of the two block is v.
Feel free to ask for more if needed or if you did not understand something.
Answer:
Vf = - 3 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.
where:
Vf = final velocity [m/s]
Vo = initial velocity = - 7 [m/s]
a = acceleration = 1 [m/s²]
t = time = 4[s]
Now replacing:
Vf = -7 + (1*4)
Vf = - 3 [m/s]