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3 years ago

A 10 kg ball is traveling at the same speed as a 1 kg ball. Compared to the 10 kg ball, the 1 kg ball has

2 answers:

8 0

A 10 kg ball is travelling at the same speed as a 1 kg ball. It has 1/10 the momentum when compared to the 10 kg ball

Answer: Option 2

Explanation:

If two objects travel with same speed, then the momentum can be calculated by the following,

Consider mass of 1 kg ball is $m_{1}$

for 10 kg ball as $m_{2}$

Velocity is same for both so it is v

Momentum, $p=mass \times velocity$

Then, $p_{1}=1 \times v=v$

$p_{2}=10 \times v=10 v$

When substituting for v as $p_{1}$ , we get $p_{2}=10 p_{1}$

$p_{1}=\frac{1}{10} p_{2}$

From this, we know momentum of 1 kg ball is 1/10 times that of 10 kg ball.

Zepler [3.9K]3 years ago

7 0

The answer is the second option, or 1/10 the same momentum.

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A 90 kg person stands at the edge of a stationary children's merry-go-round at a distance of 5.0 m from its center. The person s

Paraphin [41]

Answer:

$\omega = 0.016\,\frac{rad}{s}$

Explanation:

The rotation rate of the man is:

$\omega = \frac{v}{R}$

$\omega = \frac{0.80\,\frac{m}{s} }{5\,m}$

$\omega = 0.16\,\frac{rad}{s}$

The resultant rotation rate of the system is computed from the Principle of Angular Momentum Conservation:

$(90\,kg)\cdot (5\,m)^{2}\cdot (0.16\,\frac{rad}{s} ) = [(90\,kg)\cdot (5\,m)^{2}+20000\,kg\cdot m^{2}]\cdot \omega$

The final angular speed is:

$\omega = 0.016\,\frac{rad}{s}$

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3 years ago

What was Galileo’s contribution to the study of motion?

babunello [35]

Before giving you the answer straight away, I’d like to make sure you understand each option.

FIRST OPTION

“He developed the three laws of motion."

This option is not only the incorrect answer, but it is an incorrect statement. Galileo did not develop the three laws of motion. Isaac Newton was the one to compiled the three laws of motion.

SECOND OPTION

“He was the first to systematically study force and motion."

This option is a statement is true, and it could also be the correct answer. Galileo Galilei used experiments to search for the cause of motion.

THIRD OPTION

“He was the first to discover gravity."

This option is not only the incorrect answer, but it is an incorrect statement. Galileo was not the person to discover gravity. Sir Isaac Newton was the first to discover gravity.

FINAL OPTION

“He improved on Newton's laws."

This option is not only the incorrect answer, but it is an incorrect statement. Galilei did not improve Sir Isaac Newton’s laws.

Now that we’ve gone through each of the options individually, we can go ahead and determine the correct answer to the question, which is...

B ) He was the first to systematically study force and motion.

- Marlon Nunez

8 0

3 years ago

Read 2 more answers

How much power does a crane develop doing 60,000 J of work in 5.00minutes?

larisa [96]

Answer: 200W

Explanation: P = W/T

60,000 / (5*60) = 200

4 0

2 years ago

A 10 gauge copper wire carries a current of 23 A. Assuming one free electron per copper atom, calculate the magnitude of the dri

Reptile [31]

Question:

A 10 gauge copper wire carries a current of 15 A. Assuming one free electron per copper atom, calculate the drift velocity of the electrons. (The cross-sectional area of a 10-gauge wire is 5.261 mm².)

Answer:

3.22 x 10⁻⁴ m/s

Explanation:

The drift velocity (v) of the electrons in a wire (copper wire in this case) carrying current (I) is given by;

v = $\frac{I}{nqA}$

Where;

n = number of free electrons per cubic meter

q = electron charge

A = cross-sectional area of the wire

First let's calculate the number of free electrons per cubic meter (n)

Known constants:

density of copper, ρ = 8.95 x 10³kg/m³

molar mass of copper, M = 63.5 x 10⁻³kg/mol

Avogadro's number, Nₐ = 6.02 x 10²³ particles/mol

But;

The number of copper atoms, N, per cubic meter is given by;

N = (Nₐ x ρ / M) -------------(ii)

Substitute the values of Nₐ, ρ and M into equation (ii) as follows;

N = (6.02 x 10²³ x 8.95 x 10³) / 63.5 x 10⁻³

N = 8.49 x 10²⁸ atom/m³

Since there is one free electron per copper atom, the number of free electrons per cubic meter is simply;

n = 8.49 x 10²⁸ electrons/m³

Now let's calculate the drift electron

Known values from question:

A = 5.261 mm² = 5.261 x 10⁻⁶m²

I = 23A

q = 1.6 x 10⁻¹⁹C

Substitute these values into equation (i) as follows;

v = $\frac{I}{nqA}$

v = $\frac{23}{8.49*10^{28} * 1.6 *10^{-19} * 5.261*10^{-6}}$

v = 3.22 x 10⁻⁴ m/s

Therefore, the drift electron is 3.22 x 10⁻⁴ m/s

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3 years ago

What are three common clues that a chemical change has occurred

ddd [48]

The substance has changed, It dissolved, and it evaproted.

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