Gravity is a non contact force , jump from a little high place (don't do that :P) , you wont just get stuck in the air you will fall down , this is gravity you dont need any contact
Answer:
C, A and E
Explanation:
In theory you always assume that the prostive is going to the negtive and since C, A and E are in series they all will turn off will turn off
Answer:
Answer:
6.68 x 10^16 m/s^2
Explanation:
Electric field, E = 3.8 x 10^5 N/C
charge of electron, q = 1.6 x 10^-19 C
mass of electron, m = 9.1 x 10^-31 kg
Let a be the acceleration of the electron.
The force due to electric field on electron is
F = q E
where q be the charge of electron and E be the electric field
F = 1.6 x 10^-19 x 3.8 x 10^5
F = 6.08 x 10^-14 N
According to Newton's second law
Force = mass x acceleration
6.08 x 10^-14 = 9.1 x 10^-31 x a
a = 6.68 x 10^16 m/s^2
Explanation:
Answer: 3- Large cells of rising and sinking gasses
Explanation: Hotter gas coming from the radiative zone expands and rises through the convective zone. It can do this because the convective zone is cooler than the radiative zone and therefore less dense. As the gas rises, it cools and begins to sink again. As it falls down to the top of the radiative zone, it heats up and starts to rise. This process repeats, creating convection currents and the visual effect of boiling on the Sun's surface.
Answer:

Explanation:
Given that
Length = L
At initial over hanging length = Xo
Lets take the length =X after time t
The velocity of length will become V
Now by energy conservation

So

We know that



At t= 0 ,X=Xo
So we can say that

So the length of cable after time t
