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3 years ago

What is the answer to -134>-a+2(-7-7a)

Mathematics

1 answer:

maw [93]3 years ago

6 0

Answer:

the answer is a > 8

i hope this helps!!

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Please help me solve this

vekshin1

Answer:

Option C

Step-by-step explanation:

Since it's draining, it means it must start at a certain value and end at a maximum of 0 since water cannot ever be less than 0. Since it's original amount is 40, it can only start draining from 40 and end at max 0 hence 0 ≤ y ≤ 40

Topic: inequalities

If you like to venture further, feel free to check out my insta (learntionary). I'll be constantly posting math tips and notes! Thanks!

5 0

2 years ago

Read 2 more answers

A number is added to 13. The result is then multiplied by 2 to give a new result of 52. What is the number ?

Andreyy89

Hi, so I first I divided 52 by 2 and ended up with 26. 26-13 is 13.

The answer is 13

Check my work 13+13 =26

26 times 2 is 52

5 0

3 years ago

Please, please help!

tensa zangetsu [6.8K]

$General \: line \: equation: y=mx+b \\ \Rightarrow y = \frac{2}{x} \: and \: y = 6{ x }^{2} - 7 \: won 't \: be \: lines \: when \: graphed$

4 0

3 years ago

Security fence encloses a rectangular area on one side of a park in a city. three sides of fencing are used, since the fourth s

LiRa [457]

Hi,
Let assume a the width and b the length of the rectangular area.
$\left \{ {{2a+b=116} \atop {a*b=1682}} \right. \\\\

 \left \{ {{b=116-2a} \atop {a*(116-2a)=1682}} \right. \\\\

 \left \{ {{b=116-2a} \atop {a^2-58a+841=0}} \right. \\\\

 \left \{ {{b=116-2a} \atop {(a-29)^2=0}} \right. \\\\

 \left \{ {{a=29} \atop {b=116-2*29}} \right. \\\\

 \left \{ {{a=29} \atop {b=58}} \right. \\\\






$

6 0

3 years ago

Enter the coordinates of the vertices of r(180,0) and t(3,-2) (QRST) will give crown

Viktor [21]

Answer:

Step-by-step explanation:

From the graph attached,

Coordinates of the vertices are,

Q(1, 3), R(3, -3), S(0, -2) and T(-2, 1)

Following the rule of translation by 3 units to the right and 2 units down $T_{(3, -2)}$

(x, y) → (x+3, y-2)

Q(1, 3) → Q''(4, 1)

R(3, -3) → R"(6, -5)

S(0, -2) → S"(3, -4)

T(-2, 1) → T"(1, -1)

Following rule $r_{(180,\text{O})}$ (rotation of a point by 180° about the origin) will give the image points,

(x, y) → (-x, -y)

Q"(4, 1) → Q'(-4, -1)

R"(6, -5) → R'(-6, 5)

S"(3, -4) → S'(-3, 4)

T"(1, -1) → T'(-1, 1)

7 0

3 years ago