Pin supports, such as that at A, may have horizontal and vertical components to the support reaction. Roller supports, such as t
1 answer:
Answer:
hello your question is incomplete below is the missing part of the question and attached is the missing diagram
In the simply-supported beam shown in the figure below, d1=14 ft, d2=7 ft, and F=15 kips. so find Az, Ay, By.(in kips)
answer :
Reaction force at B = 10 kips
Reaction force in the y axis = 5 kips
Reaction force in the Z direction = 0 kips
Explanation:
Taking moment about point A
∑ Ma = 0
By + ( d1 + d2 ) - F*d1 = 0
By ( reaction force at B ) = ( 15 * 14 ) / ( 21 ) = 10 kips
Applying equilibrium forces in the Y-axis
∑ Fy = 0
Ay - F + By = 0
where : F = 15, By = 10
hence ; Ay = 5 kips
applying equilibrium forces in the Z-direction
∑ Fz = 0
Az = 0 kips
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Answer:
T = 20.42 N
Explanation:
given data
standard altitude = 30,000 ft
velocity Ca = 500 mph = 0.4 m/s
inlet areas Aa = 7 ft² = 0.65 m²
exit areas Aj = 4.5 ft² = 0.42 m²
velocity at exit Cj = 1600 ft/s = 487.68 m/s
pressure exit j = 640 lb/ft² = 0.3 bar
solution
we get here thrust of the turbojet that is express as
thrust of the turbojet T = Mg × Cj - Ma × Ca + ( j Aj -
a Ag ) .............1
here Ma = Mg
Ma = a × Ca Aa = 0.042 kg/s
put value in equation 1 we get
T = 0.042 × (487.68 -0.14) + ( 0.3 × - 0.3 × 0.65 )
T = 20.42 N