Answer:
the elongation of the metal alloy is 21.998 mm
Explanation:
Given the data in the question;
K = σT/ (εT)ⁿ
given that metal alloy true stress σT = 345 Mpa, plastic true strain εT = 0.02,
strain-hardening exponent n = 0.22
we substitute
K = 345 / 
K = 815.8165 Mpa
next, we determine the true strain
(εT) = (σT/ K)^1/n
given that σT = 412 MPa
we substitute
(εT) = (412 / 815.8165 )^(1/0.22)
(εT) = 0.04481 mm
Now, we calculate the instantaneous length
= 
given that 
= 480 mm
we substitute
=
× 
= 501.998 mm
Now we find the elongation;
Elongation = 
we substitute
Elongation = 501.998 mm - 480 mm
Elongation = 21.998 mm
Therefore, the elongation of the metal alloy is 21.998 mm
Answer:
1. You have the courage to help without expecting a reward.
2. Because actions are more eloquent than words. Actions are far more valuable and counted than words, and that's how she inspired me.
3. Doing simple things that can make someone grateful and happy without knowing that someone is inspired and motivated by your good deeds, and also doing some interesting things By.
Explanation:
Answer:
A force must s applied to a wall or roof rafters to add strength and keep the building straight and plumb
Answer:
BOD concentration at the outflow = 17.83 mg/L
Explanation:
given data
flow rate of Q = 4,000 m³/day
BOD1 concentration of Cin = 25 mg/L
volume of the pond = 20,000 m³
first-order rate constant equal = 0.25/day
to find out
What is the BOD concentration at the outflow of the pond
solution
first we find the detention time that is
detention time t = 
detention time t = 
detention time = 5 days
so
BOD concentration at the outflow of pond is express as
BOD concentration at the outflow = 
here k is first-order rate constant and t is detention time and Cin is BOD1 concentration
so
BOD concentration at the outflow = 
BOD concentration at the outflow = 17.83 mg/L
