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ipn [44]
2 years ago
14

The moisture content in air (humidity) is measured by weight and expressed in pounds or ____________________.

Engineering
1 answer:
VikaD [51]2 years ago
3 0

Moisture content is measured in terms of pounds of water per pound of air (lb water/lb air) or grains of water per pound of air (gr. of water/lb air).

Hope this helps❤

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16 engineering design process
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iejf go jjflkkkfffnfb ffv jedj HD video for my homework and I will be

Explanation:

for my homework and I will bemdjdjhdghy g<u>et</u><u> a</u><u> chance</u><u> to</u><u> look</u><u> at</u><u> the</u><u> </u><u>calendar</u><u> please</u><u> find</u><u> my</u><u> attached</u><u> updated</u><u>g</u><u> </u><u>my</u><u> homework</u><u> and</u><u> I</u><u> will</u><u> be</u><u> there</u><u> at</u><u> the</u><u> same</u><u> time</u><u> I</u><u> will</u><u> be</u><u> there</u><u>g</u><u> </u><u>my</u><u> homework</u><u> and</u><u> I</u><u> need</u>

6 0
3 years ago
What is operant conditioning
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6 0
4 years ago
Select three possible deliverables that might be specified in a project charter.
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In a balanced three-phase Y-Y system, the source is an abc sequence of voltages and Van 100 20° V rms. The line impedance per phase is 0.6 + j1.2 N, while the per-phase impedance of the load is 10 + j14 Q. Calculate the line currents and the load voltages.
4 0
3 years ago
In dynamics, the friction force acting on a moving object is always a) in the same direction of its motion b) a kinetic friction
FrozenT [24]

Answer:

B) a kinetic friction

Explanation:

 The force of friction in a movement object its called kinetic friction force (<em>fk).              </em>The net force acting in the direction of the movement its express, according to the Newton second law, like this: F- <em>fk. </em>That expression says that the net force produces an aceleration in the direction of the movement of the object.

 Now if the force its removed, the <em>fk</em> its continue acting in the object but now in the opposite direction. And according to the Newton second law this <em>fk </em>it going to continue acting until the object stay in a still state.

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6 0
3 years ago
A beam of span L meters simply supported by the ends, carries a central load W. The beam section is shown in figure. If the maxi
saw5 [17]

Answer:

W = 11,416.6879 N

L ≈ 64.417 cm

Explanation:

The maximum shear stress, \tau_{max}, is given by the following formula;

\tau_{max} = \dfrac{W}{8 \cdot I_c \cdot t_w} \times \left (b\cdot h^2 - b\cdot h_w^2 + t_w \cdot h^2_w \right )

t_w = 1 cm = 0.01

h = 29 cm = 0.29 m

h_w = 25 cm = 0.25 m

b = 15 cm = 0.15 m

I_c = The centroidal moment of inertia

I_c = \dfrac{1}{12} \cdot \left (b \cdot h^3 - b \cdot h_w^3 + t_w \cdot h_w^3 \right )

I_c = 1/12*(0.15*0.29^3 - 0.15*0.25^3 + 0.01*0.25^3) = 1.2257083 × 10⁻⁴ m⁴

Substituting the known values gives;

I_c = \dfrac{1}{12} \cdot \left (0.15 \times 0.29^3 - 0.15 \times 0.25^3 + 0.01 \times 0.25^3 \right )  = 1.2257083\bar 3 \times 10^{-4}

I_c = 1.2257083\bar 3 × 10⁻⁴ m⁴

From which we have;

4,500,000 = \dfrac{W}{8 \times 1.225708\bar 3 \times 10 ^{-4}\times 0.01} \times \left (0.15 \times 0.29^2 - 0.15 \times 0.25^2 + 0.01 \times 0.25^2 \right )

Which gives;

W = 11,416.6879 N

\sigma _{b.max} = \dfrac{M_c}{I_c}

\sigma _{b.max} = 1500 N/cm² = 15,000,000 N/m²

M_c = 15,000,000 × 1.2257083 × 10⁻⁴ ≈ 1838.56245 N·m²

From Which we have;

M_{max} = \dfrac{W \cdot L}{4}

L = \dfrac{4 \cdot M_{max}}{W} = \dfrac{4 \times 1838.5625}{11,416.6879} \approx 0.64417

L ≈ 0.64417 m ≈ 64.417 cm.

4 0
3 years ago
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