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Mekhanik [1.2K]
3 years ago
11

¿Por qué la lógica de proposiciones es conocida también como lógica de las proposiciones sin analizar?

Engineering
1 answer:
Ganezh [65]3 years ago
6 0
CHICKEN WING CHICKEN WING HOT DOG AND BALONEY CHICKEN AND MACORONI
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Mention verious medium level and higher level human resources related to engineering​
aliya0001 [1]

Answer:

Engineering aims to allow technical parts, structures and/or systems, such as those of a machine, to fulfill their function. To this end, occurring and/or desired processes (the operation thereof) are investigated and elaborated. Appropriate parts are designed individually or in a team, occurring stresses are calculated and the parts to be produced are modeled and/or specified on technical drawings. In some fields, maintenance is a standard part of the work to be performed. For a large part of engineering, standards and agreements have been drawn up with a view to the desired safety and practical applicability.

8 0
2 years ago
Electrical circuits must be locked-out/tagged-out before electricians work on any equipment. Is this true or false?
dybincka [34]

Answer:

true

Explanation:

Equipment that are "locked-out/tagged-out" <em>prevent the electrician from being electrocuted</em> or attaining a serious injury in relation to it. Locking out an equipment prevents it from releasing its energy because such energy can be <em>hazardous</em> to the electrician. There are instances when the equipment accidentally starts up, thus, it is essential that the equipment's source of energy is<em> isolated.</em>

8 0
3 years ago
Assuming that the following three variables have already been declared, which variable will store a Boolean value after these st
Yuki888 [10]

Answer:

C

Explanation:

Boolean Algebra deals with either a one or a zero and how to manipulate them in computers or elsewhere. The "choice" option may not work, since for text it must be enclosed in quotation marks, usually. For "again," it's text and not a 1 or 0. So, the answer is C, since this is a 0.

5 0
3 years ago
A 3.5-m3 rigid tank initially contains air whose density is 2 kg/m3 . The tank is connected to a high-pressure supply line throu
Mumz [18]

Answer:

Explanation:

First, we find the mass of the air originally in the tank.

Density is given as mass divided by volume. It is given as:

Density = \frac{mass}{volume}

Therefore, mass is:

mass = denisty *volume

Density of air = 2 kg/m^3; Volume of the tank =  3.5 m^3

=> Mass = 3.5 * 2 = 7 kg

The mass of the air initially in the tank is 7 kg.

After air is allowed to enter, the mass changes.

New density = 6.5 kg/m^3

The new mass will be:

Mass = 6.5 * 3.5 = 22.75 kg

We can now find the mass of air that has entered the tank:

Mass of air that entered tank = New mass of air - Original mass of air

M = 22.75 - 7.0 = 15.75 kg

The mass of air that entered the tank is 15.75 kg.

6 0
3 years ago
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