Answer:
x = 1178 games
Step-by-step explanation:
Let the number of games = x
Let the total cost = Tc
Let the total revenue = Tr
Given the following data;
Investment = $10,000
Cost of each game = $1.50
Selling cost = $9.99
Total cost, Tc = (Cost of each game * Number of games) + Investment
Tc = 1.50x + 10000
Total revenue, Tr = Selling cost * Number of games
Tr = 9.99x
Breakeven point is when total cost is equal to total revenue;
Tc = Tr
x = 1177.86 ≈ 1178 games.
<em>Therefore, the number of games that must be sold before the business breaks even is 1178 games. </em>
Answer:
Step-by-step explanation:
2005 AMC 8 Problems/Problem 20
Problem
Alice and Bob play a game involving a circle whose circumference is divided by 12 equally-spaced points. The points are numbered clockwise, from 1 to 12. Both start on point 12. Alice moves clockwise and Bob, counterclockwise. In a turn of the game, Alice moves 5 points clockwise and Bob moves 9 points counterclockwise. The game ends when they stop on the same point. How many turns will this take?
$\textbf{(A)}\ 6\qquad\textbf{(B)}\ 8\qquad\textbf{(C)}\ 12\qquad\textbf{(D)}\ 14\qquad\textbf{(E)}\ 24$
Solution
Alice moves $5k$ steps and Bob moves $9k$ steps, where $k$ is the turn they are on. Alice and Bob coincide when the number of steps they move collectively, $14k$, is a multiple of $12$. Since this number must be a multiple of $12$, as stated in the previous sentence, $14$ has a factor $2$, $k$ must have a factor of $6$. The smallest number of turns that is a multiple of $6$ is $\boxed{\textbf{(A)}\ 6}$.
See Also
2005 AMC 8 (Problems • Answer Key • Resources)
Preceded by
Problem 19 Followed by
Problem 21
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.
Answer:
C, D
Step-by-step explanation:
This equation can be solved any of several ways. One that doesn't require much thought is using the quadratic formula.
For ax² +bx +c = 0, the solutions are ...
In the given equation, a=2, b=11, c=5, so this becomes ...
The solutions are ...
C. x = -5
D. x = -1/2
_____
My personal favorite is using a graphing calculator. The solutions are the x-intercepts of the expression on the left. That is, where its value is zero, as the equation says.
Answer:
D -13
Step-by-step explanation:
5x - 3y - z if x = -2, y = 2, and z = -3
5x - 3y - z =
= 5(-2) - 3(2) - (-3)
= -10 - 6 + 3
= -16 + 3
= -13
