Having to do with turning a fraction over defines the word ____

The boiling point of a substance is a chemical property true or false

pogonyaev

Explanation:

vraiLe point d'ébullition est la température à laquelle une substance passe de la phase liquide à la phase gazeuse

4 0

4 years ago

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Identify the elemant that is a nonmetal , a gas, and has an element symbol that starts with the letter a

lukranit [14]

The element that is a nonmetal, a gas, and has an element symbol that starts with the letter a is Ar (Argon).
Element Ar (Argon) is the third member of noble gases, in period 8, and makes up about 1% of the Earth's atmosphere. It has approximately the same solubility as oxygen and it is 2.5 times as soluble in water as nitrogen. It is an inert element that is colorless and odorless in both its liquid and gaseous forms.

6 0

4 years ago

In a solution, the solute is the substance in the smaller amount. True False

blondinia [14]

The substance that is in the smaller amount is the solute. so yes, the answer is true.

6 0

3 years ago

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Compare the chemical a d structural formulas of butane and isobutane

defon

Butane and isobutane are structural isomers. Isobutane is produced by the isomerization reaction of butane.
CH3CH2CH2CH3--(t°,AlCl3)-›CH3CH(CH3)-CH3.
They have the same chemical formula C4H10.But structural formulas are different
Butane CH3CH2CH2CH3
Isobutane CH3CH(CH3)CH3
Isobutane has methyl radical.

5 0

4 years ago

Find the enthalpy of neutralization of HCl and NaOH. 87 cm3 of 1.6 mol dm-3 hydrochloric acid was neutralized by 87 cm3 of 1.6 m

olga nikolaevna [1]

Explanation:

The reaction equation for the given reaction will be as follows.

$HCl + NaOH \rightarrow NaCl + H_{2}O$

Each mole of both HCl and NaOH gives one mole of water.

Also, it is given that 1 liter of NaOH and HCl solution contains 1.6 mol $dm^{-3}$ of NaOH (HCl).

It is known that 1 $cm^{3}$ = 0.001 liter. So, 87 $cm^{3}$ = 0.087 liter.

Hence, number of moles of water obtained from the given reaction are as follows.

0.087 liter × 1.6 mol = 0.1392 moles

No. of moles = $\frac{mass}{molar mass of water}$

0.1392 moles = $\frac{mass}{18 g/mol}$

mass = 2.5056 g

Now, volume of water present before the reaction is $2 \times 0.087$ liter = 0.174 liter or 0.174 Kg (as density is 1 $Kg/cm^{3}$ ) or 174 g (as 1 kg = 1000 g).