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lina2011 [118]
3 years ago
11

\ce{Zn + CuCl2 -> ZnCl2 + Cu}Zn+CuCl2 ​ ​ ZnCl2 ​ +Cu

Chemistry
1 answer:
Kruka [31]3 years ago
3 0

Answer:

0.321 mole of ZnCl₂ have been produced from 21 g of Zn

Explanation:

The reaction is this one:

Zn (s) + CuCl₂ (aq) →  ZnCl₂ (aq)  + Cu(s)

A redox one.

If the CuCl₂ is available in excess, we consider the limiting reactant, Zn.

Molar mass Zn = 65.38 g/m

Mass / Molar mass = Mol

21 g/ 65.38 g/m = 0.321 mole

As ratio is 1:1, I will produce the same amount of mole, so I'll make 0.321 mole of ZnCl₂

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Which element forms more than one binary<br> compound with chlorine?<br><br> Са<br> Fe<br> Li<br> Zn
exis [7]

Answer:

fe

Explanation:

forms one binary compounds with chlorine

5 0
3 years ago
Use the following information to calculate the concentration, Ka and pka for an unknown monoprotic weak acid. (8 pts.) 20.00 mL
lisov135 [29]

Answer:

Concentration: 0.185M HX

Ka = 9.836x10⁻⁶

pKa = 5.01

Explanation:

A weak acid, HX, reacts with NaOH as follows:

HX + NaOH → NaX + H2O

<em>Where 1 mole of HX reacts with 1 mole of NaOH</em>

To solve this question we need to find the moles of NaOH at equivalence point (Were moles HX = Moles NaOH).

18.50mL = 0.01850L * (0.20mol / L) = 0.00370 moles NaOH = Moles HX

In 20.0mL = 0.0200L =

0.00370 moles HX / 0.0200L = 0.185M HX

The equilibrium of HX is:

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

And Ka is defined as:

Ka = [H⁺] [X⁻] / [HX]

<em>Where [H⁺] = [X⁻] because comes from the same equilibrium</em>

As pH = 2.87, [H+] = 10^-pH = 1.349x10⁻³M

Replacing:

Ka = [H⁺] [H⁺] / [HX]

Ka = [1.349x10⁻³M]² / [0.185M]

Ka = 9.836x10⁻⁶

pKa = -log Ka

<h3>pKa = 5.01</h3>
6 0
3 years ago
Which formula contains two nonmetals
VLD [36.1K]

Answer:

Nonmetal + Nonmetal —> covalent compound (usually)

Explanation:

Covalent compounds are formed when two nonmetals react with each other.

7 0
3 years ago
Explain why seeing a gas doesn not always indicate that there was a chemical change. ​
Orlov [11]
A change of state (which is a physical change) can cause gas.
7 0
3 years ago
The tarnish that forms on objects made of silver is solid silver sulphide. This can be removed by reacting it with aluminium met
steposvetlana [31]

Answer:

5.83 mol.

Explanation:

  • From the balanced reaction:

<em>2Al + 3Ag₂S → 6Ag + Al₂S₃,</em>

It is clear that 2 mol of Al react with 3 mol of Ag₂S to produce 1 mol of Ag and 1 mol of Al₂S₃.

Al reacts with Ag₂S with (2: 3) molar ratio.

<em>So, 2.27 mol of Al reacts completely with 3.4 mol of Ag₂S with (2: 3) molar ratio.</em>

<em />

  • The limiting reactant is Ag₂S.
  • The excess "left over" reactant is Al.

The reamining moles of excess reactant "Al" = 8.1 mol - 2.27 mol = 5.83 mol.

6 0
3 years ago
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