CS2 + 3O2 = CO2 + 2SO2
1 mole of CS2 gives 1 mole of CO2
12 + 2(32) = 76g of CS2 yields 44 g of CO2
Theoretically 1 g of CS2 yields 44/76 g CO2
Therefore 50 g CS2 should yield 50*44 / 76 = 28.95 g
So % yield = 103.6 % ( which is not possible because you can't create matter from nothing).
The 30g cannot be right . This is experimental err.
Answer:
<u><em>See attachment for explanations.</em></u>
Explanation:
Volume of osmium = 1.01(0.223)(0.648) = 0.14595 cm3
Density = mass / volume
So density x volume = mass of osmium
22.6 x 0.14595 = 3.29845 g
Answer:
x = 4.5
4.5 moles of C2H6 is required to produce 13.5 moles of H2O
Explanation:
Given equation is :
2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
if it requires 2 moles of C2H6 to produce 6 moles of H2O
then x moles of C2H6 is required to produce 13.5 moles of H2O
Using unitary method for solving, we get
x = 13.5 x 2 / 6
x = 13.5 / 3
x = 4.5
Therefore, 4.5 moles of C2H6 is required to produce 13.5 moles of H2O