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elena-14-01-66 [18.8K]
3 years ago
6

Sum of series 1 +1/3 +1/3².... is?​

Mathematics
1 answer:
Charra [1.4K]3 years ago
7 0

Answer:

The sum of the series is 3/2

Step-by-step explanation:

Given

1 + 1/3 + 1/3^2 + ....

Required

The sum of the series

This implies that we calculate the sum to infinity.

We have:

a = 1 -- The first term

First, calculate the common ratio (r)

r = \frac{1}{3^2} / \frac{1}{3}

Change to product

r = \frac{1}{3^2} * \frac{3}{1}

Solve

r = \frac{1}{3}

The sum of the series is then calculated as:

S_{\infty} = \frac{a}{1 - r}

S_{\infty} = \frac{1}{1 - 1/3}

Solve the denominator

S_{\infty} = \frac{1}{2/3}

Express as product

S_{\infty} = 1 * \frac{3}{2}

S_{\infty} = \frac{3}{2}

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2 years ago
2(x+11) = -26 show all work pls
Degger [83]

Answer:

x = -24

Step-by-step explanation:

First, distribute 2 to all terms within the parenthesis:

2(x + 11) =

2 * x = 2x

2 * 11 = 22

2x + 22 = -26

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. PEMDAS is the order of operations, and stands for:

Parenthesis

Exponents (& Roots)

Multiplications

Divisions

Additions

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First, subtract 22 from both sides of the equation:

2x + 22 (-22) = -26 (-22)

2x = -26 - 22

2x = -48

Next, divide 2 from both sides of the equation:

(2x)/2 = (-48)/2

x = -48/2

x = -24

x = -24 is your answer.

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