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3 years ago

escribe the differences between the terrestrial and jovian planets and classify each of the 8 planets to the proper type

Physics

2 answers:

Radda [10]3 years ago

6 0

Answer:

*******

Explanation:

is obviously the correct answer they are both so different yet so alike

Reika [66]3 years ago

5 0

wrong question someone just comment the right answer ;-;

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An object is thrown with a horizontal velocity of 49.0 mt/sec and a vertical velocity 18.8 mt/sec. How long with the object take

UNO [17]

Answer:

49.0 x18.8 ur answer i think

Explanation:

7 0

3 years ago

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Sunshine Corporation is expected to pay a dividend of $1.50 in the upcoming year. Dividends are expected to grow at the rate of

grigory [225]

Answer:

$25

Explanation:

The computation of the intrinsic value of the stock is shown below:

As we know that

Intrinsic value or Price = Dividend ÷ (Cost of equity - growth rate)

where,

Cost of equity or ke is

= Risk free rate of return + beta × (Market rate of return - risk free rate of return)

= 6% + 0.75 × (14% - 6%)

= 12 %

So the intrinsic value is

= $1.50 ÷ (12% - 6%)

= $25

7 0

3 years ago

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In California the pacific plate slides past the North American plate. If the pacific plate is moving at a speed of 5 centimeters

RUDIKE [14]

Answer:

2000years

Explanation:

We will either convert the distance to centimeters or speed to meters/second.

Converting distance to centimeters: 100 meters= 100*100centimeters =10000centimeters.

time=distance/speed

t=10000/5=2000 years

5 0

3 years ago

A giant wall clock with diameter d rests vertically on the floor. The minute hand sticks out from the face of the clock, and its

Katyanochek1 [597]

Answer:

$d_{x}(t)=(D/2)cos(\frac{\pi}{30}*t)$

Explanation:

We can try writing the equation of the horizontal component of the length of the minute hand in terms of distance and the angle, that depends of time in this particular case.

The x-component of the length of the minute hand is:

$d_{x}(t)=dcos(\theta (t))$ (1)

d is the length of the minute hand (d=D/2)
D is the diameter of the clock
t is the time (min)

Now, using the angular kinematic equations we can express the angle in term of angular velocity and time. As we know, the minute hand moves with a constant angular velocity, so we can use this equation:

$\theta (t)=\omega *t$ (2)

Also we know, that the minute hand moves 90 degrees or π/2 rad in 15 min, so using the definition of angular velocity, we have:

$\omega=\frac{\Delta \theta}{\Delta t}=\frac{\theta_{f}-\theta_{i}}{t_{f}-t{i}}=\frac{\pi/2-0}{15-0}=\frac{\pi}{30}$

Now, let's put this value on (2)

$\theta (t)=\frac{\pi}{30}*t$

Finally the length x(t) of the shadow of the minute hand as a function of time t, will be:

$d_{x}(t)=(D/2)cos(\frac{\pi}{30}*t)$

I hope it helps you!

6 0

3 years ago

suppose a car of 1200kg is moving with a velocity of 40km/hr therefore its kinetic energy is not zero. 1. explain briefly what h

mezya [45]

Answer:

Explanation:

For starters begin with a warning not to touch the brake drums. All of the KE is transferred to the brake drums. The result is a large rise in temperature. Heat. If you press hard on the brakes, rubber is left on the road and there is heat involved in that too.

8 0

3 years ago

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