Answer:
16 m/s.
Explanation:
The following data were obtained from the question:
Mass of truck = 5000 Kg
Velocity of truck = 8 m/s
Mass of car = 2500 kg
Velocity of car =..?
Next, we shall determine the momentum of the truck. This can be obtained as follow:
Mass of truck = 5000 Kg
Velocity of truck = 8 m/s
Momentum of truck =.?
Momentum = mass × velocity
Momentum = 5000 × 8
Momentum of the truck = 40000 Kg.m/s
Finally, we shall determine the velocity of the car as follow:
From the question given above, we were told that the car and truck has the same momentum.
This implies that:
Momentum of the truck = momentum of car = 40000 Kg.m/s
Thus, the velocity of the car can be obtained as shown below:
Mass of car = 2500 kg
Momentum of the car = 40000 Kg.m/s
Velocity of car =..?
Momentum = mass × velocity
40000 = 2500 × velocity
Divide both side by 2500
Velocity = 40000/2500
Velocity = 16 m/s
Therefore, the velocity of the car is 16 m/s.
Answer:
Satellite D has a mass (kg) of 500 and the distance from Earth (km) is 320.
Explanation:
The universal law of gravitation states that the force between two objects in the universe is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
We have to choose the satellite having greatest gravitational force with earth. In all options the distance from the earth is same i.e. 320 km. So, we have to select the satellite having maximum mass because the mass of the earth is constant.
Hence, the correct option is (D) " Satellite D has a mass (kg) of 500 and the distance from Earth (km) is 320 ".
Answer:
Acceleration, 
Explanation:
Given that,
The plane is at rest initially, u = 0
Final speed of the plane, v = 72.2 m/s
Time, t = 29 s
We need to find the average acceleration for the plane. It can be calculated as :
So, the average acceleration for the plane is 
. Hence, this is the required solution.
Answer:
The Balmer series refers to the spectral lines of hydrogen, associated to the emission of photons when an electron in the hydrogen atom jumps from a level 
to the level 
.
The wavelength associated to each spectral line of the Balmer series is given by:
where 
is the Rydberg constant for hydrogen, and where 
is the initial level of the electron that jumps to the level n = 2.
The first few spectral lines associated to this series are withing the visible part of the electromagnetic spectrum, and their wavelengths are:
656 nm (red, corresponding to the transition 
)
486 nm (green, 
)
434 nm (blue, 
)
410 nm (violet, 
)
All the following lines lie in the ultraviolet part of the spectrum. The limit of the Balmer series, corresponding to the transition 
, is at 364.6 nm.
