All categories

3 years ago

Define steam distillation

Physics

1 answer:

Blizzard [7]3 years ago

4 0

Answer:

Steam distillation is a separation process which consists in distilling water together with other volatile and non-volatile components.

You might be interested in

A strongman applies a constant force of 2000 N to a car of mass 1000 kg, which is initially at rest. (a) What is the acceleratio

Charra [1.4K]

Answer:

(a) Acceleration $a=2m/sec^2$

(b) Distance s = 25 m

Explanation:

We have given constant force F = 2000 N

Mass of the car = 1000 kg

(a) From newton's law we know that F = ma

So $2000=1000\times a$

$a=2m/sec^2$

(b) Tine is given as t = 5 sec

As the car is initially at rest so initial velocity u = 0 m/sec

From second equation of motion $s=ut+\frac{1}{2}at^2$

So $s=0\times 5+\frac{1}{2}\times 2\times 5^2=25m$

4 0

3 years ago

What is the frequency of microwaves with wavelength of 20-mm? (c = 3.0 x 10^8 m/s) a.15 GHz b.100 MHz c. 400 MHz d. 73 GHz

gtnhenbr [62]

Let's assume these microwaves are traveling in a vacuum, then this equation holds true:

c = fλ

c is the speed of light in a vacuum, f is the frequency, and λ is the wavelength.

Given values:

c = 3×10⁸m/s

λ = 20×10⁻³m

Plug in the values and solve for f:

3×10⁸ = f(20×10⁻³)

f = 15GHz

Choice A

6 0

3 years ago

A 0.01 kg spring toy is compressed 0.02 m and released vertically. The toy is measured to reach 0.25 m in the air. Determine the

Scorpion4ik [409]

Answer:

122.5 N/m

Explanation:

According to the law of conservation of energy, if there is no air resistance or frictional forces, the initial elastic potential energy of the spring toy is entirely converted into gravitational potential energy when the toy reaches the highest point.

Therefore, we can write:

$\frac{1}{2}kx^2=mgh$

where the term on the left is the initial elastic potential energy while the term on the right is the gravitational potential energy, and where

k is the spring constant

x = 0.02 m is the compression of the spring

m = 0.01 kg is the mass of the toy

h = 0.25 m is the height reached by the toy

$g=9.8 m/s^2$ is the acceleration due to gravity

Solving for k,

$k=\frac{2mgh}{x^2}=\frac{2(0.01)(9.8)(0.25)}{(0.02)^2}=122.5 N/m$

8 0

3 years ago

A gannet is a seabird that fishes by diving from a great height

antoniya [11.8K]

For constant acceleration along a given direction, we can relate acceleration, velocity and position with the following equation that doesn't involve time:
$v^{2}= v_{0}^{2}+2a(x- x_{0})$
In this equation x is the final position, which we take to be 0. Also the initial velocity Vo is zero. Thus the equation simplifies to
$v^{2}= 2a(- x_{0})$
Putting in v=32m/s, a=-9.81m/s^2 gives
$32^{2}= 2(-9.81)(- x_{0})
$
$\frac{32^{2}}{2*9.81}= x_{0}=52.19m$

3 0

3 years ago

Solve each of the following initial value problems and plot the solutions for several values of y0. (A computer algebra system i

e-lub [12.9K]

Answer:

a) y-8 = (y₀-8) $e^{t}$ , b) 2y -5 = (2y₀-5) $e^{2t}$

Explanation:

To solve these equations the method of direct integration is the easiest.

a) the given equation is

dy / dt = and -8

dy / y-8 = dt

We change variables

y-8 = u

dy = du

We replace and integrate

∫ du / u = ∫ dt

Ln (y-8) = t

We evaluate at the lower limits t = 0 for y = y₀

ln (y-8) - ln (y₀-8) = t-0

Let's simplify the equation

ln (y-8 / y₀-8) = t

y-8 / y₀-8 = $e^{t}$

y-8 = (y₀-8) $e^{t}$

b) the equation is

dy / dt = 2y -5

u = 2y -5

du = 2 dy

du / 2u = dt

We integrate

½ Ln (2y-5) = t

We evaluate at the limits

½ [ln (2y-5) - ln (2y₀-5)] = t

Ln (2y-5 / 2y₀-5) = 2t

2y -5 = (2y₀-5) $e^{2t}$

c) the equation is very similar to the previous one

u = 2y -10

du = 2 dy

∫ du / 2u = dt

ln (2y-10) = 2t

We evaluate

ln (2y-10) –ln (2y₀-10) = 2t

2y-10 = (2y₀-10) $e^{2t}$

5 0

3 years ago

Define steam distillation​

Define steam distillation