Given that a car is in the road, there is only movement in the x-direction. There is no movement in the y-direction.
Looking at the y-direction for the normal force:
F = N - mg
0 = N - mg, (no movement in y-dir.)
N = mg
N = (990)(9.8)
N = 9702 newtons
The normal force exerted on the car by the road is 9702 newtons.
Answer:
Part a)
Part b)
Explanation:
As the uniform sphere is rolling down the inclined plane then the net force on the sphere is given as
also we have torque equation on it
for pure rolling
now we have
now we have
now given that
so we have
Part b)
If the inclined plane is frictionless then the acceleration is given as
Answer:
Explanation:
If Ek is the kinetic energy and m is the mass and v is the velocity then v can be calculated as follows
Ek= 1/2 ×( m × v² )
2Ek= mv²
2Ek/m = v²
v =√(2Ek/m)
m = 0.1 kg
v= √(2x8/0.1)= 12.65 m/s
Answer:
Volume of water displaced = 450 - 375 = 75 ml
Vr = volume of rock = 75 ml
Wr = 9.22 - 7.60 = 1.62 N weight of 75 ml of rock
Density of rock = 1.62 N / 75 ml = .0216 N / ml
Density of water = 1000 g / 1000 ml = 9.8 N / 1000 ml = .0098 N / ml
Density of rock / density of water = .0216 / .0098 = 2.20
